The zeroes of the given polynomial is 1 and -6.
<h3>What is Polynomials?</h3>
A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.
Here, given equation;
f(x) = (x - 1)(x + 6)
for finding the zeros of the equation we need to put.....f(x) = 0
0 = (x - 1)(x + 6)
x - 1 = 0 or x + 6 = 0
x = 1 or x = -6
Thus, The zeroes of the given polynomial is 1 and -6.
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Answer: f(a-2) = 2a² - 14a + 28
Step-by-step explanation:
f(x) = 2x² - 6x + 8
you can take a-2 and substitute it for each x, which would look like this:
f(a-2) = 2(a-2)² - 6(a-2) + 8
then distribute those in ( )
f(a-2) = 2a² - 8a + 8 - 6a + 12 + 8
combine like terms
f(a-2) = 2a² - 14a + 28
Answer:
(-8,4)
Step-by-step explanation:
Given: 2x-3y=-28 and x+6y=16
solve for a variable and then substitute back into other equation
x + 6y = 16
x = 16 - 6y; now use this in the other equation
2x - 3y = -28; substitute into x
2(16 - 6y) - 3y = -28; distribute 2
32 - 12y - 3y = -28; combine y's
32 - 15y = -28; isolate 15y
32 + 28 = 15y; add the numbers
60 = 15y; divide by 15
y = 4
Now use this to plug into other equation
x + 6y = 16; y=4
x + 6(4) = 16;
x + 24 = 16; subtract 24 from both sides
x = -8
Answer:
(-3 ,-4)
I have made it in above picture
hope it helps
