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NemiM [27]
2 years ago
10

PLZ PLZ PLZ PLZ PLZ PLZ HELP ME I DONT UNDERSTAANDDDD I NEED ANSWERS SOME OF THEM I ACCIDENTLY CLICKED ON WHEN I TOOK THE PICTUR

E PLZZZZZZZZZZZZZZZ X

Mathematics
2 answers:
Solnce55 [7]2 years ago
8 0

Answer:

3rd option

Step-by-step explanation:

Leto [7]2 years ago
8 0

Answer:

answer: 706.5

Hope that helps!

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Match column a to column b​
solmaris [256]

Answer:

Straight 180

Reflex 210

Right 90

Acute 75

Obtuse 135

Step-by-step explanation:

3 0
2 years ago
Just need help with changing the y-intercepts of the asymptotes :) please help asap!!!
horrorfan [7]

Answer:

why do you need do give almost ALL your points when people and your one only question???????????

5 0
2 years ago
Can someone help me with this one math problem ? picture is below
Scorpion4ik [409]
I am not sure on how to do this however here is a link with information thst will be able to help you around this subject.i hope this helps
https://www.bbc.com/bitesize/guides/z8k887h/revision/1
4 0
2 years ago
Read 2 more answers
Derive the equation of the parabola with the focus <br> is (-7,5) and the directrix of y=-11
Volgvan
So, notice, the focus point is at -7, 5, and the directrix is at y = -11.

keep in mind that the vertex is half-way between those two fellows, and the distance from the vertex to either one of them is "p" units, check the picture below.

with that focus point and that directrix, the half-way over the axis of symmetry will be -7, -3, that's where the vertex is at, and notice the distance "p", is 8 units.

since the parabola is opening upwards, "p" is positive 8.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;4p(x- h)=(y- k)^2&#10;\\\\&#10;\boxed{4p(y- k)=(x- h)^2}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ( h, k)\\\\&#10; p=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;h=-7\\&#10;k=-3\\&#10;p=8&#10;\end{cases}\implies 4(8)[y-(-3)]=[x-(-7)]^2&#10;\\\\\\&#10;32(y+3)=(x+7)^2\implies y+3=\cfrac{1}{32}(x+7)^2&#10;\\\\\\&#10;y=\cfrac{1}{32}(x+7)^2-3

8 0
2 years ago
Solve by elimination<br> 5x+4y = 12<br> 3x - 3y = 18<br><br> Please help solve and provide steps.
SOVA2 [1]
First you solve for y.
5x+ y= 12 so Y= 12-5x
And plug it into the next equation
3x- 3(12-5x) = 18
Distribute
3x-36+15x=18
Add 36 to both sides
3x+ 15x= 54
18x= 54 ... divide
x= 3
And you can plug in x to solve for Y
5(3) + y = 12
15+ y = 12 ...subtract 15 from both sides
y= -3
4 0
3 years ago
Read 2 more answers
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