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Darina [25.2K]
3 years ago
5

In the data set shown below, what is the value of the quartiles? (42, 43, 44, 44, 48, 49,50 )

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

first arrange the data from ascending to descending order

since they are already in the order we dont need to change

first quartile(Q1)=(N+1)/4

=7+1/4

=8/4

=2 nd term

=43

second quartile(Q2 or median)=(N+1)/2

=7+1/2

=8/2

=4 th term

=44

third quartile(Q3)=3(N+1)/4

=3(7+1)/4

=3*8/4

=24/4

=6 th term

=49

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From the information given, we have:

Two angles (<L and <M) in ∆LMN that are congruent to two corresponding angles (<O and <P) in ∆OPQ.

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when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%​
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She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

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  • Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

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∴ The selling price of an orange = \frac{160}{90}=\frac{16}{9}

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∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = \frac{20}{100} × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

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- Divide both sides by 0.8

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Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is \frac{20}{9}

- Find 20% of \frac{20}{9}

∵ Profit = 20% × \frac{20}{9} = \frac{20}{100}.\frac{20}{9}=\frac{4}{9}

- Add \frac{4}{9} to cost price to find the selling price

∴ The selling price of an orange = \frac{20}{9} + \frac{4}{9}

∴ The selling price of an orange = \frac{24}{9}

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ \frac{24}{9}

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

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