Let's say you want to compute the probability
where
converges in distribution to
, and
follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing
such that its mean and variance are the same as those for
.
Example: If
is binomially distributed with
and
, then
has mean
and variance
. So you can approximate a probability in terms of
with a probability in terms of
:
where
follows the standard normal distribution.
2. He can break his strand of 10 blocks into 3 3 times 4. I think it is 74 blocks are needed.
There’s no question or problem to this
Answer:
We need a picture or link
Step-by-step explanation:
1/1/2 is the answer ............