Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
I believe the answer is 275 miles. Hope this helps!
So what you have to do is make the denominators equal. You do that by finding out what number they can both go into which is 60. 12 can go into 60 5 times and so you have to do 9/12 times 5 which is 40/60. then 5 goes into 60 12 times so you have to do 1/5 times 5 which is 12/60. Then you see that 40/60 >12/60 therefore the class ate more of the pepperoni pizza
Answer:
1st question
A) no the table does not represent a linear function
B) the slope ( average rate of change)is 2
2nd question
A) yes the table represent a linear function
B) the slope( average rate of change) is 6
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Answer:
35°
Step-by-step explanation:
The central arc is equal to the arc that subtends it, then
arc AC = 75° and
BC = AC - AB = 75° - 40° = 35°
