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Alexus [3.1K]
2 years ago
7

There are 16 female performers in a dance recital. The ratio of men to women is 3:4. How many men are in

Mathematics
1 answer:
weqwewe [10]2 years ago
8 0

Answer:

eh its 12 because

Step-by-step explanation:

according to my calculations if there are 16 females therefore the ratio is 3 to 4 men to women 3x4=12 and 4x4=16 so the answer is 12

i might be wrong please let me know

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2. Find the area of the shaded region. Express your answer in terms of
In-s [12.5K]

Answer:

Step-by-step explanation:

Find the area of the rectangle. A = length * width

Find the area of each circle.   A = π*radius*radius

Subtract the area of each circle from the area of the rectangle.

A = length * width

A = (3+6+9+12) * 18

A = 30 * 18

A = 540 square inches

Bottom circle

A = π * radius * radius.  (radius is 1/2 of the diameter)

A = 3.14 * 6 * 6

A = 133.04 square inches

Middle circle

A = π * radius * radius

A = 3.14 * 4.5 * 4.5

A = 63.59 square inches

Top circle

A = π * radius * radius

A = 3.14 * 3 * 3

A = 28.26 square inches

Subtract the circles from the rectangle.

540 - 133.04 - 63.59 - 28.26 = 315.11 square inches is the area of the shaded part.

8 0
2 years ago
What inequality describes the weight range of a single nickel
Evgen [1.6K]

Answer:

4.806 g ≤ n ≤ 5.194 where n is the mass of a nickle.

Step-by-step explanation:

The problem tells us the weight can vary by .194 g, this means it can be up to .194 lighter and 194 heavier.  Well what value is .194 lighter and .194 heavier?  4.806 and 5.194 respectively.  So that means a nickle can be anywhere in that range, which tells us the inequality.

5 0
3 years ago
Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0
lorasvet [3.4K]

Answer:

equation;

(x + 4) {}^{2}  + (y - 2) {}^{2}  = 27

Center (-4,2)

Radius is

3 \sqrt{3}

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

(x - h) {}^{2}  + (y - k)  {}^{2}  =  {r}^{2}

Where (h,k) is center

r is the radius

So first we group like Terms together

{x}^{2}  + 8x  +  {y}^{2}  - 4y - 7 = 0

Add 7 to both sides

{x}^{2}  + 8x +  {y}^{2}  - 4y = 7

( {x}^{2}  + 8x) +(  {y}^{2}  - 4y) = 7

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

(\frac{8}{2} ) {}^{2}  = 16

and

( - \frac{4}{2} ) {}^{2}  = 4

so we have

{x}^{2}  + 8x + 16 +  {y}^{2}  - 4y + 4y = 7 + 16 + 4

{x}^{2}  + 8x + 16  +  {y}^{2}  - 4y + 4y = 27

(x + 4) {}^{2}  +  (y  - 2) {}^{2}  = 27

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

\sqrt{27}  = 3 \sqrt{3}

So the radius is 3 times sqr root of 3.

8 0
2 years ago
Solve for the variable: 2x - 28 = 16
svlad2 [7]
2x = 44
44/2 = x
X= 22
4 0
3 years ago
Read 2 more answers
Find the slope of the line<br> The slope is m=
Elza [17]

the slope should be -1/2, hope this helps!

5 0
3 years ago
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