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irakobra [83]
2 years ago
11

Apply the distributive property to create an equivalent expression. (1−2g+4h)⋅5

Mathematics
1 answer:
alex41 [277]2 years ago
5 0

Answer:

Step-by-step explanation:

distribute 5 in parenthesis means you multipy each term by 5

5*1-5*2 g+5*4h = 5-10g+20h

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Staci is attending a music festival. The ticket to the festival costs $87.96 . Staci plans to purchase $30.00 t-shirts from the
mafiozo [28]

Step one: 200-87.96=112.04

Step two: 112.04÷30≈3.7

Step three: 3.7↔3

Answer: Staci can buy 3 shirts

5 0
2 years ago
Point A, B and C are colinear, and B lies between A and C. If AC= 48, AB= 2x+2 and BC= 3x+6, what is BC?
Degger [83]
First, u have to find x so u set up this equation:
2x+2+3x+6=48
Then solve to get:
5x+8 = 48
5x=40
X=8


Then, u substitute 8 in the expression 3x+6:
3(8) +6
Ur final answer is 30.
6 0
3 years ago
76 cm a 52 cm Find the area of the regular pentagon (the answer has one digit after the decimal point)​
alekssr [168]

Answer:

98.8 cm²

Step-by-step explanation:

Hi there!

A=\frac{1}{2} Pa where P is the perimeter of the pentagon and a is the apothem (the line going from the center of the pentagon one edge)

<u>1) Find the perimeter</u>

P=5l where l is the side length

Plug in the side length 7.6 cm

P=5(7.6)\\P=38

Therefore, the perimeter of the pentagon is 38 cm.

<u>2) Find the area</u>

A=\frac{1}{2} Pa

Plug in the perimeter (38) and the apothem (5.2)

A=\frac{1}{2} (38)(5.2)\\A=\frac{1}{2} (38)(5.2)\\A=\frac{1}{2} (197.6)\\A=98.8

Therefore, the area of the pentagon is 98.8 cm².

I hope this helps!

5 0
3 years ago
Find the quantity represented by each percent. 120% of $590
Stella [2.4K]
120% of 590=1.20*590=708.
For x% of a number y, the answer is x/100*y.
5 0
3 years ago
Read 2 more answers
Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) . Write the coordinate notation for a translation of 8 units right
Dovator [93]
Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .

Rule: (x, y)→(x + 8, y + 1 )

J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)


J’ (6,3)
K’ (5,-3)
L’ (9,-1)


Hope this helps!
3 0
2 years ago
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