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3 years ago

Help in dying please

Mathematics

1 answer:

Mkey [24]3 years ago

7 0

Answer:

hello! :) i hope your having a wonderful day :)

Step-by-step explanation:

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What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?

spayn [35]

Answer: 6,8 and 10

Step-by-step explanation:

To find the length , all we need to find is the distance between each point ,

the formula for calculating distance between two points is given by :

D = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

Let the points be :

A ( -5,-1)

B(-5,5)

C(3,-1)

Calculating the length AB , we have

D1 = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

D1 = $\sqrt{(-5+5)^{2}+(5+1)^{2}}$

D1 = $\sqrt{36}$

D1= 6

Calculating the length AC , we have

D2 = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

D2 = $\sqrt{(3+5)^{2}+(-1+1)^{2}}$

D2 = $\sqrt{64}$

D2 = 8

Calculating the length BC , we have

D3 = $\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}$

D3 = $\sqrt{(3+5)^{2}+(-1-5)^{2}}$

D3 = $\sqrt{100}$

D3 = 10

Therefore ,the length of the sides of the triangle are 6,8 and 10

3 0

3 years ago

Find the distance between the two points in simplest radical form.<br> (1,8)(6,-4)

dezoksy [38]

Distance in simplest radical form is 13

Or root 169

8 0

3 years ago

1. Graph the system of inequalities.

Tamiku [17]

see attached picture of how graph should look.

search through word for a graph icon, you should be able to do this in Word.

4 0

3 years ago

In the Volume of Cylinders, Cones and Spheres section, what is the volume of a sphere with a radius of 6in? *

Rudiy27

Answer:

The volume of the sphere is 288π in³

Step-by-step explanation:

To calculate the volume of a sphere we have to use the following formula:

V = volume

r = radius

V = ⁴⁄₃πr³

V = ⁴⁄₃ * π * (6in)³

V = π * ⁴⁄₃ * 216 in³

V = 288π in³

The volume of the sphere is 288π in³

4 0

4 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago

Help in dying please​

Help in dying please