All categories

3 years ago

4x+3y-2x where x=8 and y=12

Mathematics

2 answers:

Luba_88 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

vesna_86 [32]3 years ago

3 0

The answer should be 52

You might be interested in

Evaluate the expression when x = 3 and y = 5.

MakcuM [25]

Step-by-step explanation:

x = 3 and y = 5.

1: 2xy

2 x 3 x 5

=30

2: 6y divided by x

6 x 5 / 3

30/3

=10

3:4y- x

4 x 5 -3

20-3

=17

4:Y(to the power of two) -7x +2

5^2 -7 x 3 + 2

25-7x3+2

25-21+2

25-19

3 0

3 years ago

The population of a city has decreased by 27% since it was last measured. If the current population is 7300, what was the previo

Tema [17]

Answer:

the answer is 9271

Step-by-step explanation:

if 7300 is 73%, then you need to add 27% to get 100% which is 9271

7 0

2 years ago

Determinați numerele prime a , b si c care verifica relațiile :

RoseWind [281]

La respuesta es B a+10b+6c=62

5 0

4 years ago

Calculate the limit of the function with L'Hospital rule

mr_godi [17]

Answer:

L=24

Step-by-step explanation:

L'Hopital's Rule for Evaluating Limits:

Rule is that if $\lim_{x \to a} \frac{f(x)}{g(x)}$ takes $\frac{0}{0}$ or $\frac{\infty}{\infty}$ form, then,

$\lim_{x \to a} \frac{f(x)}{g(x)}= \lim_{x \to a} \frac{f'(x)}{g'(x)}$

where $f'(x)=\frac{df(x)}{dx}$ and $g'(x)=\frac{dg(x)}{dx}$

Now coming to the problem,

$L= \lim_{x \to \frac{\pi}{6} } \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3} )}$

Here $f(x)=cot^{3}x-3cotx$ and $g(x)=cos(x+\frac{\pi}{3} )$

Substituting $x=\frac{\pi}{6}$ in f(x) and g(x),

$f(\frac{\pi}{6})=cot^{3}\frac{\pi}{6}-3cot\frac{\pi}{6}\\=3\sqrt{3}-3\sqrt{3}\\ =0$

$g(\frac{\pi}{6})=cos(\frac{\pi}{6}+\frac{\pi}{3})\\=cos\frac{\pi}{2}\\=0$

Since L takes the form $\frac{0}{0}$ , using l'hopital's rule

$L= \lim_{x \to \frac{\pi}{6}} \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3})}= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}x(-cosec^{2}x)-3(-cosec^{2}x)}{-sin(x+\frac{\pi}{3})}$

now substituting $x=\frac{\pi}{6}$ ,

$L= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}\frac{\pi}{6}(-cosec^{2}\frac{\pi}{6})-3(-cosec^{2}\frac{\pi}{6})}{-sin(\frac{\pi}{6}+\frac{\pi}{3})}\\=\frac{3*3^{2}(-2^{2})+3(2^{2})}{-1}\\=24$

6 0

3 years ago

PLEASE HELP ME!!!!

Alla [95]

Answer:

(A) 0 (B) f(x)≥3/2

Step-by-step explanation:

#CarryOnLearning

3 0

3 years ago

4x+3y-2x where x=8 and y=12​

4x+3y-2x where x=8 and y=12