<span>a. 2 ft. 5 in. + 9 in.=2 ft 14 in.=2 ft. (12+2) in.=3 ft. 2 in. (since 1 ft.=12 in.);
</span>
<span> b. 4 yd. 8 in + 6 yd. 6 in. =(4+6) yd. (8+6) in.=10 yd. 14 in.=10 yd. (12+2) in.=10 yd. 1 ft. 2 in.;
</span>
<span>c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. + 13 yd. 1 ft. 3 in.=(29+55+13) yd. (2+1+1) ft. (11+10+3) in.=97 yd. 4 ft. 24 in.=97 yd. (3+1) ft. (12+12) in.=98 yd. 3 ft.=99 yd.
</span>
d. 4,839 sq. yd. 8 sq. ft. 139 sq. in. + 7 sq. ft. 124 sq. in.=4,839 sq. yd. (8+7) sq. ft. (139+124) sq. in.=<span>4,839 sq. yd. 15 sq. ft. 263 sq. in. =</span>
<span>4,839 <span>sq. yd. 15 sq. ft. (144+119) sq. in.=</span></span><span>4,839 sq. yd. 16 sq. ft. 119 sq. in.=</span><span>4,839 <span>sq. yd. (9+7) sq. ft. 119 sq. in.=</span></span><span>4,840 <span>sq. yd. 7 sq. ft. 119 sq. in.</span></span>
Answer:
Grayson has to walk 1.7 miles across the field.
Step-by-step explanation:
We have drawn the diagram for your reference.
Given:
Grayson usually walks 1.5 miles west on the side walks
According to Diagram we can say;
CA = 1.5 miles
Also Given:
Grayson also walks 0.8 miles north on the sidewalks
So According to Diagram we can say;
BA =0.8 miles
Now we need to find number of miles Grayson have to walk across the field.
According to diagram we can say;
We have to find CA.
Assuming the diagram to be right angled triangle.
We can find CA using Pythagoras theorem.
Substituting the given values we get;
Taking square root on both side we get;
Hence Grayson has to walk 1.7 miles across the field.
Answer:
116*
Step-by-step explanation:
36* + 28* = 64*
180* - 64* = 116*
Answer: r=C/2π
Step-by-step explanation:
Circumference= 2πr
C=2πr
Divide both side by 2π
C/2π = 2πr/2π
r = C/2π
