Answer:
For f(x) to be differentiable at 2, k = 5.
Step-by-step explanation:
For f(x) to be differentiable at x = 2, f(x) has to be continuous at 2.
For f(x) to be continuous at 2, the limit of f(2 – h) = f(2) = f(2 + h) as h tends to 0.
Now,
f(2 – h) = 2(2 – h) + 1 = 4 – 2h + 1 = 5 – 2h.
As h tends to 0, lim (5 – 2h) = 5
Also
f(2 + h) = 3(2 + h) – 1 = 6 + 3h – 1 = 5 + 3h
As h tends to 0, lim (5 + 3h) = 5.
So, for f(2) to be continuous k = 5
Answer:
9
Step-by-step explanation:
-7 and -7 are the same and -5 and 4 are 9 spaces apary.
Hope this helps plz hit the crown <3
let the numbers be x and y
x + y = 1600 ----*
12%x = 20%y
0.12x = 0.2y
y = <u>0</u><u>.</u><u>1</u><u>2</u><u>x</u>
0.2
y = 0.6x
substitute in * eqn
x + 0.6x = 1600
1.6x = 1600
x = 1000
then,
y = 0.6*1000
y = 600
the numbers are 1000 and 600
Composite numbers are numbers that are not prime.
Answer:One solution was found : x = 12. Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the ...
Step-by-step explanation:
