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3 years ago

What are the steps to solve for: 1/5(x+5)=1/4(x-3)+1

1 answer:

3 0

Step 1. Simplify $\frac{1}{5} (x+5)$ to $\frac{x+5}{5}$

$\frac{x+5}{5} = \frac{1}{4} (x-3)+1$

Step 2. Simplify $\frac{x+5}{5}$ to $1+ \frac{x}{5}$

$1+ \frac{x}{5} = \frac{1}{4} (x-3)+1$

Step 3. Simplify $\frac{1}{4} (x-3)$ to $\frac{x-3}{4}$

$1+ \frac{x}{5} = \frac{x-3}{4} +1$

Step 4. Cancel $1$ on both sides

$\frac{x}{5} = \frac{x-3}{4}$

Step 5. Multiply both sides by $20$ (the LCM of $5,4$ )

$4x=5(x-3)$

Step 6. Expand

$4x=5x-15$

Step 7. Subtract $5x$ from both sides

$4x-5x=-15$

Step 8. Simplify $4x-5x$ to $-x$

$-x=-15$

Step 9. Multiply both sides by $-1$

$x=15$

Done! :) Hope this helps! :)

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In the equation Ax + By = C, A and B

Rudik [331]

Answer:

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3 years ago

I need help with this as soon as possible!

Kay [80]

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2 years ago

What is the slope in the equation: y=4x+3

kompoz [17]

Answer:

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Step-by-step explanation:

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3 years ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

$f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....$

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

$fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}$

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3 years ago

Solve for the variable "a" in this equation. Show work: c=8πab

Contact [7]

C=8πab
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3 years ago