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2 years ago

Does anyone know if each square weighs 5 pounds. what is the weight of a single triangle?

Mathematics

1 answer:

steposvetlana [31]2 years ago

4 0

3 pounds bc there is 5 triangles for 15 pounds of squares

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PLEASE HELP DUE IN 20 MINUTES FIND X AND SHOW YOUR WORK PLEASE

Vlad1618 [11]

Answer:

x = 7°

Step-by-step explanation:

3x° - 53° = x° + 67°

2x° = 14°

x° = 7°

3 0

2 years ago

Need help! Law of cosines...find b round to the nearest tenth please

dusya [7]

ANSWER

$B = 27.8 \degree$

EXPLANATION

The law of cosine is given by the formula:

${b}^{2} = {a}^{2} + {c}^{2} - 2bc \cos(B)$

From the diagram,

a=17, b=8, c=16

We substitute the given values into the formula to obtain:

${8}^{2} = {17}^{2} + {16}^{2} - 2(17)(16)\cos(B)$

$64 = 289+ 256- 544\cos(B)$

$64 = 545- 544\cos(B)$

$64 - 545 = - 544\cos(B)$

$- 481 = - 544\cos(B)$

$\frac{ - 481}{ - 544} = \cos(B)$

$cos(B) = 0.88419$

$B = \cos ^{ - 1} (0.88419)$

$B = 27.8 \degree$

3 0

3 years ago

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WRITING FUNCTIONS Write a rule for the function. + -2 -1 0 2 4 16

Papessa [141]

It’s a function because the number doesn’t repeat

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2 years ago

Which congruence statements are true? Choose all answers that are correct? A: B: C: D:

tester [92]

Answer:

Correct choices are A and C

Step-by-step explanation:

Inscribed angles property: The inscribed angles subtended by the same arc are equal.

1. Angles EFH and EGH are both inscribed angles subtended by the arc EH. Therefore, these angles are congruent (option A is true).

2. Angles GHF and GEF are both inscribed angles subtended by the arc GF. Therefore, these angles are congruent (option C is true).

3. Angles EGH and FHG are interior angles of the triangle KGH and can be congruent (if triangle is isosceles) or can be not congruent (in general). Thus, option B is false.

4. Angles EFH and FHG in general are not congruent. They can be congruent only when arcs EH and FG have the same measure. In general, option D is false.

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2 years ago

Let f be continuous on [0, a] and differentiable on (0, a), Prove that if f(a)=0 then there is at least one value of x in (0, a)

asambeis [7]

Answer:

See picture attached

Step-by-step explanation:

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3 years ago