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Triss [41]
3 years ago
6

Each square on a chessboard. 2.7 inches on each side. What area of one square on chessboard. HURRY I NEED THIS TMR

Mathematics
1 answer:
kramer3 years ago
5 0
2.7 * 2.7 = 7.29

Hope this helps
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Find the value of the expression m − 4.6 for m = 7.
stich3 [128]

Answer:

2.4

Step-by-step explanation:

If you replace m with 7, the expression is now 7-4.6.

7-4.6=2.4

The value of the expression is 2.4.

-hope it helps

3 0
2 years ago
45.83333333 as a fraction
hammer [34]

Answer:

275/6

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
10 watermelons have an average weight of 4.3 pounds and 5 pumpkins have an average weight of 3.4 pounds. What is the average wei
bagirrra123 [75]
Since the average is the sum divided by the count, the sum is the average times the count.

So the sum of the weights of the watermelons is 10(4.3)=43 pounds.

The sum of the weights of the pumpkins are 5(3.4)=17 pounds

The sum of the weight of the fruits is 43+17=60 pounds

Dividing by 15 fruits gives an average item weight of 60/15 = 4 pounds

6 0
3 years ago
Read 2 more answers
What is the value of the following expression when p=4?<br><br> 4p+9
Gelneren [198K]

Answer:

4p+9=

(first start with multiple or division division from right to left then with addition from right to left)

4*4+9=

16+9=25

6 0
3 years ago
Derive the equation of the parabola with a focus at (3,1) and a directrix of y = 5
serg [7]
So hmmm  check the picture below

so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both

in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3

now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"

because the parabola opens downwards, "p" is negative, and thus, -2

now, let's plug all those fellows in then

\bf \begin{array}{llll}&#10;(x-{{ h}})^2=4{{ p}}(y-{{ k}})\\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;&#10;\begin{cases}&#10;h=3\\&#10;k=3\\&#10;p=-2&#10;\end{cases}\implies (x-3)^2=4(-2)(y-3)\implies (x-3)^2=-8(y-3)&#10;\\\\\\&#10;-\cfrac{(x-3)^2}{8}=y-3\implies \boxed{-\cfrac{1}{8}(x-3)^2+3=y}

5 0
3 years ago
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