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Readme [11.4K]
3 years ago
11

Sin5A-sin7A-sin4A+sin8A/cos4A-cos5A-cos8A +cos7A

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0
Sin1A/-cos1A=iddkkkk
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Five more than seven time a number is ninerty-six.what is the number?
zaharov [31]

Answer:

5x + 6 ≥ 21

Step-by-step explanation:

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How do you find the area
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You first separate the triangle from the rectangle. Then multiply one side be one side. 
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Which one is it? for a grade & due today!! help me please
Mama L [17]

Answer:the last one

Step-by-step explanation:

Divide 12 by 10.4

Hope this helps you

It might come bigger out as a decimal 1.5

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Nitrates are groundwater contaminants derived from fertilizer, septic tank seepage and other sewage. Nitrate poisoning is partic
o-na [289]

Answer:

a) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

b) n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

Part a

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior information about the population proportion we can use ase estimator \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

Part b

For thi case the estimator for p is \hat p =0.07

n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

4 0
3 years ago
What is the simplified answer to this problem 12 > -3x + 6
Verdich [7]

In this question, you're simplifying the inequality by solving for x.

Solve for x:

12 > -3x + 6

<em>flip the equation:</em>

-3x + 6 < 12

<em>subtract 6 from both sides</em>

-3x < 6

<em>divide both sides by -3, while also flipping the inequality</em>

x > -2

Answer:

x > -2

8 0
3 years ago
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