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ipn [44]
3 years ago
12

A Horse is tied with rope in the center of grassland to graze. The length of rope is 5m. The diameter of circular garden is 50m.

Find the area in which the horse cannot graze.
Mathematics
1 answer:
Eduardwww [97]3 years ago
6 0
Area of a circle is πr².  (The formula is easy to recall if you just remember the joke--πr²--no, pie are round!)

So we must calculate the difference of the areas to determine what the horse cannot reach.

As we are given the garden's diameter, we must divide it in half to get its radius.  The rope, of course, already represent a radius.

π25² - π5² = π(25² - 5²) = π(625 - 25) = π600
= 1885 square meters.
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A porch has the shape of a quarter circle. If the porch was a complete circle it would have a diameter of 5 ft. What is the appr
Sladkaya [172]
Normally, to find the area of a circle you'd do π × r^{2} so you have to find the radius by dividing 5 by 2 to get 2.5. Approximating pi as 3.14, you would do 3.14 × 2.5^{2} = 19.625. Because the porch is a quarter circle, you would then divide this by 4 to get 4.906. Rounded to the nearest square foot, your answer would therefore be 5 ft. I hope this helps!
3 0
3 years ago
A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.
Kobotan [32]

Answer:

The numbers are

-2+3\sqrt{5}   and 3\sqrt{5}

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

so

x=y-2

y=x+2 ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

so

4y+x^2=49 ----> equation B

substitute equation A in equation B

4(x+2)+x^2=49

solve for x

x^2+4x-41=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+4x-41=0

so

a=1\\b=4\\c=-41

substitute in the formula

x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}

x=\frac{-4\pm\sqrt{180}} {2}

x=\frac{-4\pm6\sqrt{5}} {2}

x=-2\pm3\sqrt{5}

so

The positive real number is

x=-2+3\sqrt{5}

Find the value of y

y=x+2

y=-2+3\sqrt{5}+2

y=3\sqrt{5}

6 0
3 years ago
A system of equations is shown below. y = -5x - 2 y=3x - 4 What is the solution to the system of equations?​
marishachu [46]

Answer:

the answer is (x,y) (1/4 -13/4)

8 0
3 years ago
Find the x- and y-intercepts for the linear equation –3x + 4y = 24.
Sav [38]

Answer:

x- intercept = - 8, y- intercept = 6

Step-by-step explanation:

To find the x- intercept let y = 0 and solve for x

- 3x + 4(0) = 24

- 3x = 24 ( divide both sides by - 3 )

x = - 8 ← x- intercept

To find the y- intercept let x = 0 and solve for y

- 3(0) + 4y = 24

4y = 24 ( divide both sides by 4 )

y = 6 ← y- intercept

3 0
3 years ago
A ball, thrown vertically upwards, from the ground, has its height h (in meters) expressed as a function of time t (in seconds),
Ivenika [448]

Answer:

pen

Step-by-step explanation:

fddefefgerf

6 0
3 years ago
Read 2 more answers
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