Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
6.32 is the final answer! :)
Answer:
12900
Step-by-step explanation:
umm first you write down the number of zeros (but only the zeros at last if a zero comes in middle or between other numbers, then you must have to multiply it) and then multiply the remaining numbers. I am not good at explaining. ;)
648 Im pretty sure if not let me know
0.5 because if you divide 3 and 6 yards it’s equal to 0.5yards. You divide the yard and the friends because they are sharing three yards. So, each friend gets 0.5 yard each.