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mafiozo [28]
2 years ago
14

Write the linear equation given two points (-6, 8) and (3, -7). *

Mathematics
1 answer:
horrorfan [7]2 years ago
6 0

\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-7}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-7}-\stackrel{y1}{8}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-6)}}}\implies \cfrac{-15}{3+6}\implies \cfrac{-15}{9}\implies -\cfrac{5}{3}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{5}{3}}[x-\stackrel{x_1}{(-6)}]\implies y-8=-\cfrac{5}{3}(x+6) \\\\\\ y-8=-\cfrac{5}{3}x-10\implies y = -\cfrac{5}{3}x-2

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Now, \sqrt{x} and -\sqrt{x} are only defined for x≥0, because only for these x'es we can take the square root. 

Note that the third graph has domain (-infinity, 0], so it is not the right one, while 1 is ok.


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Step-by-step explanation:

-6x+12=0

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Answer:

\frac{53}{12} or 4 \frac{5}{12}

Step-by-step explanation:

\frac{6}{1}  \times  \frac{1}{2}  = 3

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Now add them

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Simplified version is

4 \frac{5}{12}

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