Answer:
8
Step-by-step explanation:
You just gotta divide 64 by 8
Answer:

Step-by-step explanation:

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The applicable rules of logarithms are ...
log(ab) = log(a) +log(b)
log(a/b) = log(a) -log(b)
log(a^b) = b·log(a)
Notice that if you go forward, the common ratio is 5. Each new term is found by mult. the previous term by 5.
If, on the other hand, you go backwards (terms decreasing), then you divide a term to find what the previous term was.
Here, divide 1 by 5 to find the first term. It's 1/5.
From my notes I’ve the derivative of arctan(x)= 1/(1+x^2)
Answer:
54.90
Step-by-step explanation: