. ...
Example 2. Zn + HCl ---> ZnCl2 + H2 ...
Example 3. Ca(OH)2 + H3PO4 ---> Ca3(PO4)2 + H2O. ...
Example 4. FeCl3 + NH4OH ---> Fe(OH)3 + NH4Cl. ...
Example 5. S8 + F2 ---> SF6 ...
Example 6. C2H6 + O2 ---> CO2 + H2O. ...
Example 7. Al2(CO3)3 + H3PO4 ---> AlPO4 + CO2 + H2O. Summary
To be useful, chemical equations must always be balanced. Balanced chemical equations have the same number and type of each atom on both sides of the equation.
The coefficients in a balanced equation must be the simplest whole number ratio. Mass is always conserved in chemical reactions. mber of atoms of each element in reactants is not equal to the number of atoms of each element present in product, then the chemical equation is called unbalanced chemical equation. An equation is balanced when the same number of each element is represented on the reactant and product sides. Equations must be balanced to accurately reflect the law of conservation of matter.
Answer:
dx/dt = 0,04 m/sec
Step-by-step explanation:
Area of the circle is:
A(c) =π*x² where x is a radius of the circle
Applying differentiation in relation to time we get:
dA(c)/dt = π*2*x* dx/dt
In this equation we know:
dA(c)/dt = 0,5 m²/sec
And are looking for dx/dt then
0,5 = 2*π*x*dx/dt when the area of the sheet is 12 m² (1)
When A(c) = 12 m² x = ??
A(c) = 12 = π*x² ⇒ 12 = 3.14* x² ⇒ 12/3.14 = x²
x² = 3,82 ⇒ x = √3,82 ⇒ x = 1,954 m
Finally plugging ths value in equation (1)
0,5 = 6,28*1,954*dx/dt
dx/dt = 0,5 /12.28
dx/dt = 0,04 m/sec
Answer:
The walkway around the pool makes the entire outer dimensions (outer border)
x+9+2x3=x+15 and x+8+2x3
hope this helps! could i get brainliest plz?
Step-by-step explanation:
again, 2 unknowns.
x = number of 2- points baskets
y = number of 3- points baskets
we know they hit the basket 37 times in a so far unknown mixture of 2-point and 3- point throws.
x + y = 37
which gives us e.g.
x = 37 - y
and we know that with this unknown mixture they scored 80 points.
so,
2x + 3y = 80
as every successful 2-points throw scores 2 points, and every successful 3-points throw scores 3 points.
so, again our 2 equations :
x = 37 - y
2x + 3y = 80
remember, we prepared the first equation so that it gives us already an identity expressing one variable by the other. and that we use in the second equation :
2×(37 - y) + 3y = 80
74 - 2y + 3y = 80
74 + y = 80
y = 6
and from
x = 37 - y
we get
x = 37 - 6 = 31
so, they had 31 2-points throws and 6 3-points throws.