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guapka [62]
3 years ago
7

For a circle with a given circumference C find the radius and diameter of the circle round to the nearest whole number

Mathematics
1 answer:
Sati [7]3 years ago
8 0
This answer would be C because
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Levart [38]
The correct matches are as follows:

<span>Line Segment 
</span>E) part of a line that has two endpoints<span>

Plane 
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Perpendicular Lines 
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Hope this answers the question. Have a nice day.
4 0
3 years ago
Read 2 more answers
A patient has been ordered medication Cat a dosage of 3680 mg/day. The dosage available is 425 mg each scored tablets. • How man
Tema [17]

Answer:

  • about 8 2/3
  • 11 pm

Step-by-step explanation:

The required dosage in terms of tablets is ...

  3680 mg = (3680 mg)/(425 mg/tab) = 8.66 tabs

We don't know how the tablets are "scored", but in my experience they have a groove that facilitates them being cut in half.

We expect the nurse will administer 8 1/2 tablets per day, for a dose of 3613 mg, slightly short of the ordered 3680 mg.

__

9 doses will be administered over 8 time intervals of 2 hours, so will take until 16 hours after 7 am. The last (1/2) dose will be at 0700 +1600 = 2300 hours, or 11 pm.

3 0
3 years ago
In the diagram parallel lines f and g are intersected
elena55 [62]

Answer:

there is no diagram

Step-by-step explanation:

3 0
3 years ago
State the number of possible triangles that can be formed using the given measurements.
romanna [79]

Answer:  39) 1              40) 2

                41) 1              42) 0

<u>Step-by-step explanation:</u>

39)     ∠A = ?        ∠B = ?       ∠C = 129°

            a = ?          b = 15         c = 45

Use Law of Sines to find ∠B:

\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36°        ∠B = 15°       ∠C = 129°       is the only valid solution.

40)      ∠A = 16°        ∠B = ?       ∠C = ?

             a = 15           b = ?         c = 19

Use Law of Sines to find ∠C:

\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1:  ∠A = 16°        ∠B = 144°       ∠C = 20°    

Solution 2:  ∠A = 16°        ∠B = 4°       ∠C = 160°    

41)       ∠A = ?        ∠B = 75°       ∠C = ?

             a = 7           b = 30         c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13°        ∠B = 75°       ∠C = 92°       is the only valid solution.

42)      ∠A = ?         ∠B = 119°       ∠C = ?

             a = 34         b = 34           c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

6 0
3 years ago
Given the figures are similar, calculate the length of US
ICE Princess25 [194]

in this one x=9 ask if you need an explanation

7 0
4 years ago
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