Answer:
(-0.84, 0) and (-5.16, 0).
Step-by-step explanation:
The reference angle is the angle made with the x-axis. For two points to have the same reference angle, they would need to have the same absolute value of their tangents = y/x.
For the first pair of points: the first point has a tangent value of 1/sqrt(3), while the second has a tangent value of sqrt(3), so these are not identical.
For the second pair of points: the first point has a tangent value of -sqrt(3), while the second has a tangent value of -1/sqrt(3), so these are
not identical.
For the third pair of points: the first point has a tangent value of sqrt(3), while the second also has a tangent value of sqrt(3), so these have the same reference angle.
For the fourth pair of points: the first point has a tangent value of
1/sqrt(3), while the second has a tangent value of sqrt(3), so these are
not identical.
So the only correct answer is the third choice.
Answer:
508.68 or 508.7
Step-by-step explanation:
V=1/3(3.14)(9)^2(6)
(3.14)(81) x 6
(3.14)(486)
1/3(1526)
(divide by 3)= 508.68
Answer:
Alright the Answer to this question is
33.03 Hope this helps have a nice day :)
Step-by-step explanation:
Answer:
i) Mean = 1933.1817
ii) Range = 5684
iii) Third quartile = 6054
Step-by-step explanation:
Given data :
currency exchange rate : 1 AUD = 5.8 HKD
cost of each ounce = 2 AUD
Fixed shipping cost for each carton = 80 HKD
number of cartons = 20
next determine the total cost of the 20 cartons in HKD
= ∑(weight in ounce * cost of each ounce *exchange rate) +fixed shipping cost
= ∑ ( 160*2*5.8 + 80 ) + -------------- + (650 *2*5.8 + 80 ) ----------------- ( 1 )
= 81756 HKD
<u>i) find the mean value ( X ) </u>
= Total cost / number of cartons
= 81756 / 20 = 4087.8
ii) Find the standard deviation
= note: std = √∑(xi-X )^2 / (n-1)
= 1933.1817
<u>iii) Find the range </u>
Range = highest cost - lowest cost ( values gotten from equation 1 )
= 7650 - 1936
= 5684
<u>iv) Determine the third quartile </u>
third quartile = 6054
<em>attached below is the detailed solution</em>