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vesna_86 [32]
3 years ago
11

What is the diameter of this circle?

Mathematics
2 answers:
Aloiza [94]3 years ago
8 0

Answer:

the answer is attached to the picture

AysviL [449]3 years ago
4 0

Answer: 7

Step-by-step explanation: whhhhyyyy

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study the diagram of circle K where JL and LM are tangent to circle K at points J and M respectively. Also JL=3x+10 and ML =7x-6
Verdich [7]

Answer:

22

Step-by-step explanation:

The answer is 22. You solve the equation 3x+10=7x-6 like so

3x+10=7x-6

-3     = -3

    10= 4x-6

   +6         +6

     16=4x

      x=4

You then plug in the value of x to the equation for LM.

7x-6 becomes 7*4-6 which is 22.

7 0
4 years ago
The animal shelter had a special on adoption rates for their dogs and cats. Each dog adoption fee was $75 and each cat adoption
lidiya [134]

Answer:

3 dogs and 5 cats were adopted out on Christmas eve.

Step-by-step explanation:

Let the number of dogs adopted out on Christmas eve be x and the number of cats be y.

From the question,

On Christmas Eve, the animal adopted out 8 total animals

That is, x + y = 8 ...... (1)

and brought in $400 in total adoption fees.

Also from the question,

Each dog adoption fee was $75 and each cat adoption fee was $35.

∴ On Christmas Eve,

75x + 35y = 400 ...... (2)

Now, to determine how many dogs and how many cats were adopted out on Christmas Eve, we will solve the two equations simultaneously.

From equation (1)

x + y = 8

Make x the subject of the relation.

∴ x = 8 - y ...... (3)

Substitute the value of x into equation (2)

75(8 - y) + 35y = 400

600 - 75y + 35y = 400

600 -40y = 400

600 - 400 = 40y

200 = 40y

∴ 40y = 200

y = 200/40

y = 5

Substitute the value of y into equation (3)

x = 8 - y

x = 8 - 5

x = 3

∴ x = 3 and y = 5

Hence, 3 dogs and 5 cats were adopted out on Christmas eve.

4 0
3 years ago
You select a sample of 50 scores from a population of 2,000 scores. You compute the range and standard deviation on the sample o
nalin [4]

Answer:

The measure of dispersion which is likely to vary most between your first and second samples is the range.

Step-by-step explanation:

The range and standard deviation of a data are measures of dispersion, i.e. they measure the degree to which the data is dispersed.

The formula to compute the range is:

Range=X_{max}-X_{min}

The formula to compute the sample standard deviation is:

s=\sqrt{\frac{1}{n-1}\sum (X-\bar X)^{2} }

The sample size is: <em>n</em> = 50.

  • As the sample size is large (n = 50 > 30) the sample standard deviation (s) can be used to approximate the population standard deviation (σ). Thus, whatever the sample values be both the standard deviations can be used to approximate the population standard deviation. Hence, it can be said that both the sample standard deviations are approximately equal.
  • Whereas the range of the two samples are very likely to vary since it is based on the minimum and maximum value of the data. For both the samples the minimum and maximum value may be differ. Thus providing different range values.

Thus, the measure of dispersion which is likely to vary most between your first and second samples is the range.

5 0
4 years ago
Which construction will determine a midpoint?
likoan [24]

perpendicular bisector

5 0
4 years ago
Read 2 more answers
An ice cream company manufactures and distributes ice cream cups and cones to grocery stores. The company sells the ice cream cu
avanturin [10]

Answer: A: The 24 pack of cups has more ice cream than the 21 pack of cones.

3 0
3 years ago
Read 2 more answers
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