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2 years ago

F(x) = 2x^2 Find f(-6)

Mathematics

1 answer:

katrin2010 [14]2 years ago

7 0

Answer:

f(-6) = 72

Step-by-step explanation:

Input -6 for x :

2(-6)²

Complete with P.E.M.D.A.S :

2(36)

then :

so therefore :

f(-6) = 72

f of x equals 72

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100 points!!!!!!!!!!!!!!!!!!!!What should the numerator of the second fraction be so that the fractions are equivalent?

VladimirAG [237]

Answer:

28/3 or 9⅓

Step-by-step explanation:

2/3 = x/14

x = 2×14/3

x = 28/3

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3 years ago

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In the diagram below, R is located at (24,0), N is located at (12,18), T is located at (12,6), and E is located at (18,15). Assu

julsineya [31]

The midpoint of a segment divides the segment into equal halves

The coordinates of K are: $\mathbf{K = (12,12)}$
The coordinates of I are: $\mathbf{I = (24,24)}$
The coordinates of B are: $\mathbf{B = ( 30,33 )}$

The given parameters are:

$\mathbf{R =(24,0)}$

$\mathbf{N =(12,18)}$

$\mathbf{T =(12,6)}$

$\mathbf{E =(18,15)}$

K is the midpoint of N and T.

So, we have:

$\mathbf{K = (\frac{N_x + T_x}{2},\frac{N_y + T_y}{2})}$

This gives

$\mathbf{K = (\frac{12 + 12}{2},\frac{18+ 6}{2})}$

$\mathbf{K = (12,12)}$

E is the midpoint of T and I.

So, we have:

$\mathbf{E = (\frac{I_x + T_x}{2},\frac{I_y + T_y}{2})}$

This gives

$\mathbf{(18,15) = (\frac{I_x + 12}{2},\frac{I_y+ 6}{2})}$

Multiply through by 2

$\mathbf{(36,30) = (I_x + 12,I_y+ 6)}$

By comparison

$\mathbf{I_x + 12 = 36.\ I_y + 6 =30}$

So, we have:

$\mathbf{I_x= 24.\ I_y =24}$

Hence, the coordinates of I are:

$\mathbf{I = (24,24)}$

I is the midpoint of E and B.

So, we have:

$\mathbf{I = (\frac{E_x + B_x}{2},\frac{E_y + B_y}{2})}$

This gives

$\mathbf{(24,24) = (\frac{18 + B_x}{2},\frac{15 + B_y}{2})}$

Multiply through by 2

$\mathbf{(48,48) = (18 + B_x,15 + B_y)}$

By comparison

$\mathbf{18 + B_x = 48,\ 15 + B_y = 48 }$

So, we have:

$\mathbf{B_x = 30,\ B_y = 33 }$

Hence, the coordinates of B are:

$\mathbf{B = ( 30,33 )}$

Read more about midpoints at:

brainly.com/question/18068617

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2 years ago

Identify the terms and like terms in the expression. x² - 3x + 4 + 2x² - x - 12. Thank you to anyone who helps, I appreciate it

marta [7]

Given:

The expression is:

$x^2-3x+4+2x^2-x-12$

To find:

The terms and like terms in the expression.

Solution:

Terms: Variables, constants and product of variable and constants are known as terms which are separated by addition sign "+".

Like terms: The terms which contain same variables with same power are known as like terms.

The given expression is:

$x^2-3x+4+2x^2-x-12$

It can be rewritten as:

$x^2+(-3x)+4+2x^2+(-x)+(-12)$

Terms are $x^2,-3x,4,2x^2,-x,-12$ .

Like terms are $x^2,2x^2$ and $-3x,-x$ and $4,-12$ .

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trasher [3.6K]

Answer:

1.No- that just means that the numbers on that side are smaller

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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