<em>Answer</em><em> </em><em>:</em><em>-</em><em> </em>
<em>the</em><em> </em><em>quoti</em><em>ent</em><em> </em><em>is</em><em> </em><em>(</em><em> </em><em>4</em><em>x</em><em>²</em><em> </em><em>-</em><em> </em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>
Step-by-step explanation:
[ Refer to the attachment for steps ]
- We have to eliminate the highest degree coefficient in each step.
- And as in division of normal numbers we subtract the things here we do the same ,
but while subtracting we have to take care about the signs !
- The negative sign changes the negative sign into positive sign and positive sign into negative sign.
- Whereas , a positive sign don't changes the sign.
Answer:
6.25 km
Step-by-step explanation:
Here is the correct question: A park is 4 times as long as it is wide. If the distance around the park is 12.5 kilometers, what is the area of the park?
Given: Perimeter (Distance) of the park= 12.5 km
Considering park is in rectangular shape.
Let the width of park be x
∴ as given length will be 4x.
Formula for perimeter of rectangle =
Perimeter is given 12.5 km
⇒ 
⇒ 
∴ x= 1.25 km, which means width is 1.25 km and length is 5 km.
Now, finding the area of park
Formula; Area of rectangle= 
∴ Area of rectangle= 
∴Area of park will be 6.25 km.
Answer:
Ani age is 21
Biju age is 18
Step-by-step explanation:
let Ani age be X
let Biju age be Y
the difference of their age is 3
i.e X - Y = 3......,....(equ. 1)
let Dharam age be A
let Cathy age be B
i.e A = 2x
B = y/2
the difference of their age is 30
Y/2 - 2x = 30..... (equ. 2)
from equ.1 X = ( 3+y).........( equ.3)
y/2 - 2(3+y) = 30
y/2 - 6 + 2y = 30
multiply both side by 2
y - 6 + 2y = 60
y + 2y = 60 - 6
3y = 54
Y = 18
from equ.3
X = 3+Y where y is 18
X = 3+18 = 21
Answer:
c cuh
Step-by-step explanation:
(idk the answer)