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zlopas [31]
3 years ago
9

a line passes through (9, –9) and (10, –5).write an equation for the line in point-slope form. rewrite the equation in standard

form using integers. y 9 = (x – 9); –4x y = –45 y 9 = (x 9); –4x y = –45 y – 9 = (x 9); –4x y = 45 y – 9 = (x – 9); –4x y = 45
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0
The equation of the line in point-slope form is given by:
 y-yo = m (x-xo)

 Where,
 (xo, yo): point that belongs to the line
 m: slope of the line
 The slope is given by:
 m = \frac{y2-y1}{x2-x1}
 Substituting values:
 m = \frac{-5-(-9)}{10-9}
 Rewriting:
 m = \frac{-5+9}{10-9}
 m = \frac{4}{1}
 m=4
 Now we choose an ordered pair:
 (xo, yo) = (10, -5)

 Substituting values we have:
 y-(-5)=4(x-10)
 y+5=4(x-10)
 We now rewrite the equation in its standard form:
 y = mx + b

 Where,
 b: cut with the y axis.
 We have then:
 y = 4x - 40 - 5

y = 4x - 45
 Answer:
 point-slope form:
 y+5=4(x-10)
 or
 y+9=4(x-9)
 standard form
 y = 4x- 45
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