Maria correctly concluded that not enough information was provided to construct the requested proof. What extra information woul
1 answer:
Answer:
Hello your question is incomplete attached below is the complete question
answer: RS = ST ( option b )
Step-by-step explanation:
First we consider Δ SCA and Δ TCB
∠ SCA = ∠ TCB , ∠CAS = ∠CBT = 90°
if we assume RS = ST then ΔSRT will be termed an Isosceles triangle with its legs : SR = ST. also vertex S bisects the base of the triangle.
Δ SBR ≅ ΔSBT from here we can deduce that ; BR = BT
From the assumptions what is actually missing to contrast the proof is : RS = ST
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let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
smallest value happens at
so area is
hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145