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3 years ago

In this experiment, what is the independent variable?

Chemistry

1 answer:

Vitek1552 [10]3 years ago

7 0

Answer:

i think it would be B.

Explanation:

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Fill in the blank: after Mitosis, each daughter cell has identical

galina1969 [7]

Genes
when mitosis occurs it creates an exact copy of itself

7 0

3 years ago

How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g

Serhud [2]

Answer: The energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

Explanation:

First we have to calculate the mass defect $(\Delta m)$ .

The equation for the alpha decay of thorium nucleus follows:

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Ra}+m_{He})-(m_{Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

(Conversion factor: $1amu=1.66\times 10^{-27}kg$ )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$E=2.0916\times 10^{-13}J$

The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

Hence, the energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

5 0

3 years ago

What would cause the equilibrium to shift left in this reaction?

Lilit [14]

As per Le Chatelier's principle, if the equilibrium of a system is disturbed by changes in temperature, pressure, concentration etc then it will shift in a direction to undo the effect of the induced change.

The given reaction is:

CO + 3H2 ↔ CH4 + H2O

In this case, if the rate of the forward reaction is increased then more of the reactants get converted into products i.e. concentration of reactants decreases. In order to undo this change, the equilibrium will shift in a direction to produce more reactants i.e. to the left.

Ans: B) faster rate of forward reaction

3 0

4 years ago

Write the molecular formula of nitrate using criss cross method

exis [7]

Answer:

NO3 that is the answer to the question

8 0

3 years ago

By what factor will the rate of the reaction change if the ph decreases from 6.00 to 2.00? express your answer numerically using

jeyben [28]

The reaction equation is first order with respect to [H+]

when PH1 = -㏒[H+]1 so, when PH = 6

So by substitution:

∴ 6 = -㏒[H+]1

∴[H+]1 = 1 x 10^-6

and when PH2 = -㏒[H+]2 so, when PH2 = 2

so by substitution:

∴ 2 = -㏒[H]2

∴[H]2 = 1 x 10^-2

So the rate of reaction changes by the factor of:

[H2]2/[H]1 = (1 x 10^-2) / (1 x 10^-6) = 10000

It is 10000 times faster when PH decreases from 6 to 2

5 0

4 years ago