Question

A photon has an energy of 1.10 x 10 -13 j. What is the photon's wavelength? What type of electromagnetic radiation is it?

Answer 1

Answer:

λ  = 0.002 nm

The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.

Explanation:

Given data:

Energy of photon = 1.10 × 10⁻¹³ J.

Wavelength of photon = ?

Solution:

Formula:

E = h.c / λ

λ  = h. c / E

λ  = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.

λ  = 19.878 × 10⁻²⁶m /  1.10 × 10⁻¹³ J

λ  = 18.071 × 10⁻¹³ m

λ  = 18.071 × 10⁻¹³  × 10⁹

λ  = 18.071 × 10⁻⁴ nm

λ  = 0.002 nm

The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.