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densk [106]
3 years ago
8

Part 1: If we double each side of the second equation, 2x+y=8 we have 4x+2y=16. Explain why the same pair that is the solution t

o the system is also a solution to this new equation. If needed, you can support your explanation with hanger diagrams, or by inventing a situation that the equations represent.
Part 2: If we add the two equations in the original system, we have 6x+7y=32. Explain why the same (x, y) pair is also a solution to this equation
PLEASE ANSWER FAST
Mathematics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

Step-by-step explanation:

its the same because when you simplify it the equation is the same

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Please answer this if u have any questions on the handwriting let me know I need this for tomorrow
Setler79 [48]

Answer:

it is d

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
What is the solution of the system of equations y=x-5 , y=6
olchik [2.2K]
Y=x-5
6=x-5
6+5=x-5+5
11=x
x=11
6 0
4 years ago
5 + a < 5 true or false
Irina-Kira [14]

Answer:false


Step-by-step explanation:


3 0
3 years ago
Compare -5/6 _ -3/7 choose from 1) > 2)
vfiekz [6]

Answer

1)<2) please put 5 stars

Step-by-step explanation

First you need to find the GCF of the donominators which are 6 and 7. The GCF is 42.

6*x=42. x=7 5*7=35. -35/42 is the first fraction.

7*y=42 y=6 3*6=18. -18/42 is the second fraction.

-35/42 would be bigger but since it is negative, it is smaller.

8 0
3 years ago
Read 2 more answers
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