<span>3.60555128 is the awnser</span>
Answer:
First know this,
The volume V of a cylindrical barrel is given by the formula. V = πr2h, where r is the barrel's radius and h is the barrel's height.

Rewrite the equation as πr2h=V π r 2 h = V . Divide each term by πr2 π r 2 and simplify. Divide each term in πr2h=V π r 2 h = V by πr2 π r 2 .
Step-by-step explanation:

is regions of f ◦ g(·).
<u>Step-by-step explanation:</u>
When you multiply two functions together, you'll get a third function as the result, and that third function will be the product of the two original functions.
For example, if you multiply f(x) and g(x), their product will be h(x)=f.g(x), or h(x)=f(x)g(x).
Here we have two functions, f identifies n f regions of (0, 1)d onto (0, 1)d which is equivalent to f(x) = n f. And, g identifies n g regions of (0, 1)d onto (0, 1)d which is equivalent to g(x)= n g. Now,
⇒ ( f × g ) (x ) = f(x) × g(x)
⇒
Therefore,
is regions of f ◦ g(·).
<h3><em><u>Answers With Steps:</u></em></h3><h3>Question 1:</h3>
For the first problem, understand that you are solving for the area of a circle. The equation for the area of a circle is pi r². By using the leash length as the radius (r), you can get the answer. (The leash length is 3 meters long.)
<em>Question 1 Steps:</em>
pi 3² ---> pi * 9 ---> ≈28.27
<em>Question 1 Answer:</em>
It would have about 28.27 meters² of playable space.
<h3>Question 2:</h3>
For the second problem, it would be much the same as to the first question. There is the same objective to find the area of the circle. Along with that, it gives us a length to work with. This time it is the sprinkler's reach, which would be the radius, or "r" in the equation.
<em>Question 2 Steps:</em>
pi 5² ---> pi * 25 ---> ≈78.54
<em>Question 2 Answer:</em>
The sprinkler would have about 78.54 feet² of space that it can reach.
Answer: it is a
Step-by-step explanation: