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3 years ago

VXYZ is a kite. What is the length of XY?

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

8 0

Answer:

$5x - 6 = 3x + 4 \\ 5x - 3x = 4 + 6 \\ 2x = 10 \\ x = 10 \div2 \\ x = 5 \\ length \: of \: xy = 3 \times 5 + 4 \\ = 15 + 4 \\ = 19$

balu736 [363]3 years ago

6 0

Answer: 19

Step-by-step explanation:

From the properties of the kite, we know that line segment XY is congruent to line segment ZY. Keep in mind, the variable we need to solve for this question is x!

From this, we can say that;

3x+4=5x-6

Plus 6 on both sides to get

3x+10=5x

Minus 3x on both sides to get

10=2x

divide both sides by 2 to get

5=x

now plug the x value 5, into the equation XY

3 times 5 + 4

multiplication goes first!

15+4=19

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Answer:

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Step-by-step explanation:

The last one is also the answer

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3 years ago

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3 years ago

Read 2 more answers

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

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4 years ago

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Answer:

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