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natita [175]
3 years ago
10

VXYZ is a kite. What is the length of XY?

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

5x - 6 = 3x + 4 \\ 5x - 3x = 4 + 6 \\ 2x = 10 \\ x = 10  \div2 \\ x = 5 \\ length \: of \: xy = 3 \times 5 + 4 \\  = 15 + 4 \\  = 19

balu736 [363]3 years ago
6 0

Answer: 19

Step-by-step explanation:

From the properties of the kite, we know that line segment XY is congruent to line segment ZY. Keep in mind, the variable we need to solve for this question is x!

From this, we can say that;

3x+4=5x-6

Plus 6 on both sides to get

3x+10=5x

Minus 3x on both sides to get

10=2x


divide both sides by 2 to get

5=x


now plug the x value 5, into the equation XY

3 times 5 + 4


multiplication goes first!

15+4=19

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Answer:

the solution for x is x=40

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3 years ago
1. Given ΔQRS (is congruent to) ΔTUV, QS = 3v + 2 and TV = 7v - 6, find the length of QS and TV. Provide a detailed response bel
Morgarella [4.7K]
Because ΔQRS is congruent to <span>ΔTUV, the the segments GS and TV are also congruent due to the letter order (Q and T are first and S and V are 3rd.) Since they are congruent QS=TV. So 3v + 2 = 7v - 6
</span><span>
</span><span>Work: 
</span>3v + 2 = 7v - 6
      +6          +6
3v + 8=7v
-3v       -3v
<u>8</u> = <span><u>4v</u>
</span>4      4
2 = v

3(2) + 2 = GS
6+2 = GS
8 = GS

7(2) - 6 = TV
14-6=TV
8 = TV

Final Answer: 8=QS and 8=TV

 
3 0
3 years ago
Read 2 more answers
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

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2 years ago
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Pavlova-9 [17]

Answer:

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Step-by-step explanation:

6 0
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Let's test your knowledge!!!
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pemdas
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