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1 year ago

Write an equation in the form y = m x + b for the following table:

Mathematics

1 answer:

Gre4nikov [31]1 year ago

4 0

Answer: y=8x+6

Step-by-step explanation:

The slope is

$\frac{70-54}{8-6}=\frac{16}{2}=8$

So, the slope is 8.

Since the y-intercept is 6, the equation is y=8x+6.

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Could somebody help me I don't understand this? and can you explain how you did it.

SCORPION-xisa [38]

Answer:

77°F

Step-by-step explanation:

C = 5/9 (F - 32)

25 = 5/9 (F - 32)

-----------------------

5/9

45 = F - 32

+32 +32

------------------

77=F

6 0

2 years ago

Can someone help with this question please?

givi [52]

The answer which i calculated is suppose to be 13182ax

5 0

3 years ago

Bob harvested flour from 4 of his fields. From the first field, he harvested 13 ton of flour. The second field yielded 24 ton of

DIA [1.3K]

Bob harvested 65 tons total (13 + 24 + 14 + 14)
and as far as drawing a diagram I don't know what to tell you

hope this helps

6 0

3 years ago

Alyssa used 12 gallons of white paint for the ceiling of her kitchen and 13 gallons of white paint for her bedroom. She used

Arturiano [62]

She used 10 more gallons of green paint

Hope this helps if it does yourwelcome

6 0

2 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

2 years ago