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Nady [450]
2 years ago
7

Write an equation in the form y = m x + b for the following table:

Mathematics
1 answer:
Gre4nikov [31]2 years ago
4 0

Answer: y=8x+6

Step-by-step explanation:

The slope is

\frac{70-54}{8-6}=\frac{16}{2}=8

So, the slope is 8.

Since the y-intercept is 6, the equation is y=8x+6.

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Find the prime factorization of 2205.
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Look at the picture below

The answer is: 3×3×5×7×7 or 3²×5×7²

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3 years ago
Pleeeeaseee help me on this one like I'm really trying to pass
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Answer:

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2 years ago
Erica bought 3 1/2 yards of fabric if she uses 2/3 of the fabric how much will she have left?
RoseWind [281]
First, convert 3 1/2 into an improper fraction, which is 7/2. Now, you have to make sure both sides have a common denominator. This will be 6. So now the equation is 21/6 - 4/6. Subtract the numerators, which is 17. Keep the denominator, however. Now, simplify. You new answer will be 2 5/6. 
8 0
3 years ago
Find the 11th term of the arithmetic sequence. <br> a3 = 20.5 and a8 = 13, a11 = ______. ...?
lianna [129]
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:<span>

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.  
<span>a3 = 20.5 and a8 = 13
</span>

an = a1 + (n-1)d
20.5 = a1 + (3-1)d

</span>an = a1 + (n-1)d
13 = a1 + (8-1)d
<span>
a1 = 23.5
d = -1.5

The 11th term is calculated as follows:

a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 = 8.5</span>
8 0
3 years ago
Solve the following quadratic equation for all values of x in simplest form. (x-4)^2=33​
Brrunno [24]

\huge\text{$x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$}

To solve for x, we need to isolate it on one side of the equation.

Take the square root of both sides, making sure to use both positive and negative roots.

\begin{aligned}(x-4)^2&=33\\x-4&=\pm\sqrt{33}\end{aligned}

\sqrt{33} cannot be simplified, so we'll leave it as-is.

Add 4 to both sides to fully isolate x.

x=\pm\sqrt{33}+4

Expand the solution by making two solutions, one where \sqrt{33} is positive and one where it's negative.

x=\sqrt{33}+4,\ x=-\sqrt{33}+4\\x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}

5 0
3 years ago
Read 2 more answers
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