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3 years ago

The graphs of functions f(x) and g(x) = f(x) + k are shown below: What is the value of k?

Mathematics

1 answer:

KatRina [158]3 years ago

7 0

Answer:

k = 4

Step-by-step explanation:

k is the difference of y-intercepts (where the lines intersect with the y-axis). So, subtract the y-intercept of f(x) from the y-intercept of g(x).

2 - (-2) = 4

Hope that helps! :D

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Find the equation of the line that passes through (2,-1) and is parallel to

kap26 [50]

Answer:

Step-by-step explanation:

5 0

3 years ago

Plz help me with this questions and show working out thanks

Paraphin [41]

Answer: The steps and answers to the first two are below but you need to understand slope = change in y / change in x = y2 - y1/ x2 - x1

And you need to understand y = mx + c

m= slope c is y intercept

Substitute either point given - only use one as the x and y and find c

Step-by-step explanation:

1. You need to follow the steps -

the point is given as (2,5) = (x,y)

So what this means is x =2 and y =5

Simple substitutions is the step 5 = 3 x 2 + c

5 = 6 + c or easier to see is c + 6 =5

subtract 6 from both sides c + 6 = 5

-6 -6

__________________

c = -1

x1,y1 x2,y2

( 3,2) and (5,6) are two points on the line

you already calculate the slope which is m = noy2-y1/x2-x1 = 6-2/5-3 = 4/2 = 2

Remember y= mx + c

y = 2 x + c

now substitute in (3,2) which is (x1, y1) into the x and y in your equation

2 = 2 (3) + c

2 = 6 + c

subtract 6 from both sides

-4 = c

Now you should use this and do your last question yourself

5 0

2 years ago

Find the area of this parallelogram.

Yuki888 [10]

Area= length * height
21*9 = 189cm^2

6 0

3 years ago

Read 2 more answers

The radius of a sphere is increasing at a rate of 2 mm/s. How fast is the volume increasing (in mm3/s) when the diameter is 40 m

daser333 [38]

Answer:

$\dfrac{dV}{dt}=502.65\ mm^3/s$

Step-by-step explanation:

The volume of a sphere is given by :

$V=\dfrac{4}{3}\pi r^3$

The rate of change of volume means,

$\dfrac{dV}{dt}=\dfrac{d}{dt}(\dfrac{4}{3}\pi r^3)\\\\\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3r\times \dfrac{dr}{dt}$

We have, $\dfrac{dr}{dt}=2\ mm/s\ and\ r=40\ mm$

So,

$\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3\times 20\times 2\\\\=502.65\ mm^3/s$

So, the volume is increasing at the rate of $502.65\ mm^3/s$ .

6 0

3 years ago

In the air, it had an average speed of 16 m/s In the water, it had an average speed of 3 m/s before hitting the seabed. The tota

julia-pushkina [17]

<h2>The stone fall in air for 7 seconds and fall in water for 5 seconds.</h2>

Step-by-step explanation:

Total distance to sea bed = 127 m

Let the distance traveled in air be s.

Distance traveled in water = 127 - s

Average velocity in air = 16 m/s

Average velocity in water = 3 m/s

Distance traveled in air = Average velocity in air x Time in air

s = 16 x t₁

$t_1=\frac{s}{16}$

Distance traveled in water = Average velocity in water x Time in water

127-s = 3 x t₂

$t_2=\frac{127-s}{3}$

We have total time is 12 seconds

That is

t₁ + t₂ = 12

$\frac{s}{16}+\frac{127-s}{3}=12\\\\3s+2032-16s=576\\\\13s=1456\\\\s=112m$

We have

s = 16 x t₁

112 = 16 x t₁

t₁ = 7 s

t₁ + t₂ = 12

7 + t₂ = 12

t₂ = 5 s

The stone fall in air for 7 seconds and fall in water for 5 seconds.

7 0

3 years ago