A gardener who wants a rectangular garden whose lot perimeter is 40 meters is suggested by a fellow gardener a plan that would m
ake it so that the build would have a maximum lot area. What could be the suggestion? You must answer in a mathematical solution. Show work.
1 answer:
Answer:
a*(20-a)
Step-by-step explanation:
Let's assume that the length of the garden is a the width is b and the area is s.
b = 40/2 - a = 20-a
s =a*(20-a)=-a^2+20a=-(a-10)^2+100
then,
when a=10, max(-(a-10)^2) =0, max(s)=100
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I think it's "C"
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P.S. hope it helped. If you have any questions, I'll be glad to answer them❤
Answer:
ok
Step-by-step explanation:
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I believe the answer is A 3^7
Answer:
Option A) 
Step-by-step explanation:
The given expression is:
Taking LCM in upper and lower fractions, we get:
Therefore, the option A gives the correct answer.
Answer:
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Step-by-step explanation:
Using the FOIL Method we get this result
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