Question

A gardener who wants a rectangular garden whose lot perimeter is 40 meters is suggested by a fellow gardener a plan that would make it so that the build would have a maximum lot area. What could be the suggestion? You must answer in a mathematical solution. Show work.

Answer 1

Answer:

a*(20-a)

Step-by-step explanation:

Let's assume that the length of the garden is a the width is b and the area is s.

b = 40/2 - a = 20-a

s =a*(20-a)=-a^2+20a=-(a-10)^2+100

then,

when a=10, max(-(a-10)^2) =0, max(s)=100