C=2 times j
c=2j
o=j-6
c+j+o=58
subsitte j-6 for o and 2j for c
2j+j+j-6=58
4j-6=58
add 6 to both sides
4j=64
divide both sides by 4
j=16
sub back
c=2j
c=2(16)
c=32
o=j-6
o=16-6
o=10
curtis=32
olivia=10
jonathan=16
equations are
c+j+o=58
c=2j
o=j-6
The height of the tree is the sum of the part below the line parallel to the horizontal and the part above the line parallel to the horizontal.
Height of the part below the line parallel to the horizontal = 18 sin16° = 4.96 meters
Horizontal distance of the tip of the of the shadow from the tree = 18 cos16° = 17.30 meters
Height of the part above the line parallel to the horizontal = 17.3 tan68° = 42.83 meters
Height of the tree = 4.96 + 42.83 = 47.79 meters
It’s the last option (-6m-n+3)
1 day = 0.06 m
x = 0.96 m
0.96 ÷ 0.06 = 16 days
Step-by-step explanation:
c) since m = undefined => the equation is
x = -2
d) the equation is
y-2= -1/7 (x+7)
=> y = -1/7 x -1+2
<=> y = -1/7 x + 1
