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kupik [55]
3 years ago
12

Which value is the solution to the equation 42 ÷ j = 6?

Mathematics
1 answer:
mezya [45]3 years ago
8 0

Answer:

j = 7hope that helps!

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Kiara just bought a used car for $4,500. She plans to make payments of
lord [1]

Answer:

4 paysmenets

Step-by-step explanation:

4500/250=18 paymentent

250x4= 1,000

3 0
3 years ago
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AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA this is extra cedit in my class and i need it, can anyone help me out??
Serga [27]
A

Explanation
She gets 11 for every hour but it doesn’t say how many hours so we put a variable ( in this case x ) so we have 11x and she revived $6 extra since it was received and not taken away we add 11x +6 and since it’s an equation we put 11x +6 = $39

For extra help x is equal to 3
8 0
3 years ago
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Pls answer this math question. In a given class 12 students have cats, 15 have dogs, and 6have both. There are nine students wit
Over [174]
Working step by step I first see all my different groups then add them all together
so
12 - cats
15 - dogs
6 - both
9 - neither

12 students + 15 students + 6 students + 9 students = 42 students
therefore 42 students are in the class

16 + 10 + 3 + 12 = 41

I’m sorry if i got it wrong!
5 0
4 years ago
Read 2 more answers
URGRENNTTT PLSS HELPP 50 POINTSS!!!!! Students were asked to simplify the expression cotangent theta plus tangent theta over cot
Naddika [18.5K]

The student that simplified the expression incorrectly is student 2

<h3>How to determine the incorrect result?</h3>

The steps are given as:

\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)}

Student 1:

  • Step 1: \frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 2: 1 + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 3: 1 + tan²(Ф)
  • Step 4: sec²(Ф)

Student 2:

  • Step 1: \frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 2: \frac{1 +  \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}
  • Step 3: sec²(Ф)/tan²(Ф)
  • Step 4: csc²(Ф)

As a general trigonometry rule;

\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)} = \sec^2(\theta)

This means that student 1 is correct, while student 2 is not

The first error in student 2's workings is in step 2, where we have:

\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)} = \frac{1 +  \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}

The above expression is not justified and cannot be proved by any trigonometry rule

Since the step 2 is incorrect, the other steps cannot be used.

Hence, the student that simplified the expression incorrectly is student 2

Read more about trigonometric expressions at:

brainly.com/question/8120556

#SPJ1

5 0
2 years ago
Solve for x 4/5 x + 4/3 = 2x
Ugo [173]

Answer:

Fraction: 10/9  mixed number: 1 1/9 decimal: 1.1

Step-by-step explanation:

1. Combine 4/5 with x

4x/5+4/3=2x

move all the terms that contain x in them to your left side of the equation

-6x/5 + 4/3 =0

subtract 4/3  from both sides

-6x/5 = 4/3

multiply both side by -5/6

-5/6 (-6x/5)= -5/6 (-4/3)

x=10/9  x=1.1  x= 1 1/9

6 0
4 years ago
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