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kicyunya [14]
2 years ago
12

Solve the equation by graphing the related function: -x^2-5=0

Mathematics
1 answer:
Lina20 [59]2 years ago
6 0

Answer:

love youre profile it's from Saiki K

Step-by-step explanation:

We use the factoring form becuase our c is zero and it in standard quadratic form so we rather factor than complete the square or quadratic formula since that is longer to do than just factor.

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On Tuesday, Karen finished all her chores in 3/4 of an hour. On Wednesday, she finished her chores in 5/12 of an hour. How much
IRISSAK [1]
1 hour = 60 minutes

Tuesday: 60 divided by 4 = 15. Karen did it 3/4 of a hour so we multiply 15 by 4 which is 45. 45 equals 45 minutes. On Tuesday, Karen finished her chores in 45 minutes

Wednesday: first we divide 60 by 12 which is 5. 5 would equal 5 minutes. now we multiply 5 by 5 which is 25. Karen finished her chores in 25 minutes.

Answer: Karen finished her chores 20 minutes faster on Wednesday than Tuesday.

Hope this helps!
3 0
2 years ago
Write a rule for the linear function in the graph.
labwork [276]
3=4m+ b
-1=3m+b

m=4
plug in to either equation,
3=16+ b
b=-13

Thus, C would be the answer.
6 0
3 years ago
Read 2 more answers
If f(x)=|x|, sketch f'(x) for -2
Luden [163]

Answer:

17

Step-by-step explanation:

4 0
3 years ago
1. Find the value of
spin [16.1K]

9514 1404 393

Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

8 0
2 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
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