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Inga [223]
3 years ago
6

thfrak%5Cred%7B2%20%7B%7D%5E%7B2%7D%20%2B%204%20%7B%7D%5E%7B2%7D%20%20%20%3D%20%7D%20%5C%5C%20%20%5C%5C%20%5Chuge%5Cmathfrak%5Cgreen%7Basap%20%5C%3A%20and%20%5C%3A%20thanks%7D" id="TexFormula1" title="\huge\mathfrak\purple{please \: solve..} \\ \\ \huge\mathfrak\red{2 {}^{2} + 4 {}^{2} = } \\ \\ \huge\mathfrak\green{asap \: and \: thanks}" alt="\huge\mathfrak\purple{please \: solve..} \\ \\ \huge\mathfrak\red{2 {}^{2} + 4 {}^{2} = } \\ \\ \huge\mathfrak\green{asap \: and \: thanks}" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Verdich [7]3 years ago
8 0

Answer:

2²4

4²=16

4+16=20

hope it helps :)

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A river discharges 4 × 106 cubic feet of water into the Pacific Ocean each second. There are 86,400 seconds in one day. To find
victus00 [196]

Answer:

c option is correct oprion

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The base diameter and the height of a cone are both equal to x units. A cone has a height of x and a diameter of x. Which expres
Nostrana [21]

Answer:

1/12piX^3

Step-by-step explanation:

3 0
3 years ago
5 + (-2)=<br> A. -3<br> B. 3<br> C. -2<br> D. -5<br> E. 0
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it is b because I did the math and got that

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3 years ago
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one days discharge at its mouth, 3 trillion gallons, could supply all of country A’s household for 5 months. how much water an a
serious [3.7K]

let's use engineering notation for the sake of brevity.

1 trillion is 1,000,000,000,000, or just 1E12, twelve zeros.

1 million is then 1E6, six zeros.

we know the discharge for one day is 3E12 gallons, and that'd do just fine for country A for 5 months.  How many gallons in 1 month only?

\bf \begin{array}{ccll} gallons&months\\ \cline{1-2} 3E12&5\\ x&1 \end{array}\implies \cfrac{3E12}{x}=\cfrac{5}{1}\implies 3E12=5x \\\\\\ \cfrac{3E12}{5}=x\implies 6E11=x\implies 600000000000=x

if there are 200million inhabitants in A, namely 200E6 or 2E8 inhabitants, how many gallons per inhabitant from all those 6E11 gallons?

\bf \begin{array}{ccll} gallons&households\\ \cline{1-2} 6E11&2E8\\ x&1 \end{array}\implies \cfrac{6E11}{x}=\cfrac{2E8}{1}\implies 6E11=2E8x \\\\\\ \cfrac{6E11}{2E8}=x\implies \cfrac{600000000000}{200000000}=x\implies 3000=x

5 0
4 years ago
A warren of rabbits has a population of 350. The population is increasing at a rate of 3% per year. How can you write an exponen
koban [17]

Answer:

P(t) = 350e^{0.0025t}

Step-by-step explanation:

Exponential growth function:

The exponential growth function for a population, after t years, is given by:

P(t) = P(0)e^{rt}

In which P(0) is the initial population and r is the growth rate.

A warren of rabbits has a population of 350. The population is increasing at a rate of 3% per year.

This means that P(0) = 350, r = 0.03

So

P(t) = P(0)e^{rt}

P(t) = 350e^{0.03t}

How can you write an exponential growth function to find the monthly growth rate?

Monthly growth rate means that the time is divided by 12(as one year has 12 months), so the equation will be:

P(t) = 350e^{0.03\frac{t}{12}}

P(t) = 350e^{0.0025t}

6 0
3 years ago
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