Answer:
Graph A is correct
Step-by-step explanation:
p(x)= x/10
x= 1, 2, 3, 4
Plug in x values in p(x)
when x=1 , then P(1) = 1/10
When x=2 , then P(2) = 2/10
When x=3 , then P(3) = 3/10
When x=4 , then P(4) = 4/10
In the graph y axis has 2/10 , 4/10 , 6/10...
1/10 lies between 0 and 2/10
3/10 lies between 2/10 and 4/10
Graph A is correct
so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
Answer:
its 1,3,4,and 7
Step-by-step explanation:
i just did it
so A,C,D,and G
The first picture is for number 1 and the second one for number 2.
Answer:
The outlier is $105.
Step-by-step explanation:
An outlier is a value amongst other values that is smaller or bigger than those other values, for example, the $105 in the above equation.
