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3 years ago

JamIah's weight is 4/3 of Devi's weight. What is the ratio of Jamiah's weight to Devi's weight.

Mathematics

2 answers:

melomori [17]3 years ago

4 0

Answer:

Therefore, a ratio of 8/6 is an equivalent ratio of 4/3: in that particular ratio calculation, you should just multiply 4, as well as 3, by 2.

Step-by-step explanation:

I hope this helps! :D

Inessa [10]3 years ago

4 0

3,2 it’s simple just add the ration and remove it

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7y = 14 -28x to standard form

MissTica

Answer:

28x + 7y = 14.

Step-by-step explanation:

Just add the 28x to each side.

4 0

3 years ago

Read 2 more answers

12. The function M(h) = 10e-0.173h can be used to find the number of milligrams M of morphine that is

vodomira [7]

Answer:

Part A; Initial dosage is 10 milligrams

Part B:

8.4113 milligrams after 1 hour

5.0057 milligrams after 4 hours.

Step-by-step explanation:

It is given M(h)= 10 $e^{-0.173h}$

Initial dosage is the 10 milligrams

After 1 hour, plug in h as 1

So, M(1)=10 $e^{-0.173*1}$

Simplify the right side

M(1)=10(0.84113)

M(1)= 8.4113 milligrams.

Now, after 4 hours

M(4)=10 $e^{-0.173*4}$

M(4)=10(0.50057)

M(4) =5.0057 milligrams

3 0

3 years ago

Solve the system of equations. 10x+y=−20 y=2x2−4x−16 ( , ) and ( , )

Sladkaya [172]

I will go about solving this using the elimination method.

First, convert the equations.

10x + y = -20
4x + y = -12

Second, find the easiest variable to get rid of and get rid of it! (In this case, y) We will subtract to get rid of y.

6x = -8

Third, you want to solve the equation.

6x = -8 (divide by 6)
x = $-1 \frac{1}{3}$

Fourth, solve for y by inserting the answer for x into one of the equations.

10( $-1 \frac{1}{3}$ ) + y = -20
$-13 \frac{1}{3}$ + y = -20 (subtract $-13 \frac{1}{3}$ )
y = $-6 \frac{2}{3}$

The solution for this system of equations is ( $-1 \frac{1}{3}$ , $-6 \frac{2}{3}$ ).

7 0

3 years ago

Read 2 more answers

The table shows the diameters of three planets:

Sonbull [250]

Uranus = 530.4
Neptune = 509.6
Saturn = 126

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3 years ago

Consider the following problem: a box with an open top is to be constructed from a square piece of cardboard, 3 feet wide, by cu

Alecsey [184]

Answer:

) See annex

b) See annex

x = 0,5 ft

y = 2 ft and

V = 2 ft³

Step-by-step explanation: See annex

c) V = y*y*x

d-1) y = 3 - 2x

d-2) V = (3-2x)* ( 3-2x)* x ⇒ V = (3-2x)²*x

V(x) =( 9 + 4x² - 12x )*x ⇒ V(x) = 9x + 4x³ - 12x²

Taking derivatives

V¨(x) = 9 + 12x² - 24x

V¨(x) = 0 ⇒ 12x² -24x +9 = 0 ⇒ 4x² - 8x + 3 = 0

Solving for x (second degree equation)

x =[ -b ± √b²- 4ac ] / 2a

we get x₁ = 1,5 and x₂ = 0,5

We look at y = 3 - 2x and see that the value x₂ is the only valid root

then

x = 0,5 ft

y = 2 ft and

V = 0,5*2*2

V = 2 ft³

7 0

3 years ago