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3 years ago

Which set of numbers can represent the side lengths, in millimeters, of an obtuse triangle?

Mathematics

2 answers:

ruslelena [56]3 years ago

8 0

Answer:

A. 8 , 10 , 14 ... A edge

Step-by-step explanation:

olga_2 [115]3 years ago

3 0

The answer is actually A.

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In four years, 40% of a radioactive element decays. Find its half-life. Round to one decimal place.

White raven [17]

To find the answer, use $k = \frac{2.303 }{ 4} (log\frac {100 }{ 40})$ , and then use the equation $t=\frac{.693}{k}$ To find it's half life.

5 0

3 years ago

Read 2 more answers

Please can someone help me with this question

sasho [114]

Answer:

r = - $\frac{6a}{1-5m^2}$

Step-by-step explanation:

Rewrite the equation as $\sqrt{x} 6a+r/5r$ = m

Remove the radical on the left side of the equation by squaring both sides of the equation.

( $\sqrt{\frac{6a+r}{5r} )^{2}$ = m^2

Then, you simplify each of the equation.

Rewrite: ( $\sqrt{\frac{6a+r}{5r} )^{2}$ as $\frac{6a+r}{5r} = m^{2}$

Remove any parentheses if needed.

Solve for r.

Multiply each term by r and simplify."

Multiply both sides of the equation by 5.

6a+r= m^2r⋅(5)

Remove parentheses.

Move 5 to the left of (m ^2) r

6a+r=5m^2)r

Subtract 5m^2)r from both sides of the equation.

6a+r-5m^2)r=0

Subtract 6a from both sides of the equation.

r-5m^2)r=-6a

Factor r out of r-5m^2)r

r(1-5m^2)=-6a

Divide each term by 1-5m^2 and simplify.

r = - $\frac{6a}{1-5m^2}$

There you go, hope this helps!

4 0

3 years ago

Synthetic Division x^3+9x^2-11x-13

olga nikolaevna [1]

Answer:

You can't synthetic divide since there's no dividend. As you can't factor it so I figure you must've forgot to include something or there's no solution.

8 0

2 years ago

before tomorrow can I have a quick answer and maybe an explanation on how to answer these kinds of questions overall? need some

MA_775_DIABLO [31]

Answer:

a) maximum; the parabola opens downward

b) positive; it must lie above the x-axis

c) x = 1.5

Step-by-step explanation:

The x-intercepts of a function are the points where the graph of the function crosses the x-axis. The y-values there are zero.

The "differences" of a function are related to the average slope between adjacent points. Second differences are related to the rate of change of the slope of the function. When second differences are negative, as here, the slope of the quadratic function is decreasing, becoming more negative. We say the curvature of the function is negatve, and that it opens downward.

If the graph of the parabola opens downward, and it crosses the x-axis, it must have a maximum that is a positive value of y.

The graph of a parabola is symmetrical about its vertex. That means points on the same horizontal line are the same distance from the line of symmetry, which must go through the vertex. The x-coordinate of the vertex will be the x-coordinate of the midpoint between the two x-intercepts:

x = (-2 +5)/2 = 3/2

The x-coordinate of the vertex is x = 1.5.

______

Additional comment

The attachment shows a table with three evenly-spaced points on the curve. The calculations show first differences (d1) and second differences (d2). You can see that the sign of the second diffference is negative, in agreement with the given conditions.

3 0

2 years ago

A ladder is leaning against a building so that the distance from the ground to the top of the ladder is 22 feetfeet less than th

ivann1987 [24]

So basically the ladder is creating a right triangle with the ground and the wall. Ladder is the hypotenuse (h), building = b, ground = g
b = h - 22 ft
g = 1010 ft
use Pythagorean Theorem to determine the length of h:
${c}^{2} = {a}^{2} + {b}^{2} \\ {h}^{2} = {(h - 22)}^{2} + {1010}^{2} \\ {h}^{2} = {h}^{2} - 44h + 484 + 1020100$
The h^2 terms cancel out to = 0
$0 = - 44h + 484 + 1020100 \\ 44h = 1020584 \\ 44h \div 44 = 1020584 \div 44 \\ h = 23195.1 \: feet$

7 0

3 years ago