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charle [14.2K]
4 years ago
5

Elevator 1 in a building moved from ground position to a final position of +17 feet. Elevator 2 in the same building moved from

ground to a final position of –22 feet. Which statement best describes the final positions of these two elevators?Elevator 1 is 17 feet below ground level, and elevator 2 is 22 feet above ground level.
Elevator 1 is 17 feet above ground level, and elevator 2 is 22 feet below ground level.

Elevator 1 is 17 feet above ground level, and Elevator 2 is 22 feet below the position of Elevator 1.

Elevator 1 is 17 feet below ground level, and Elevator 2 is 22 feet above the position of Elevator 1.
Mathematics
1 answer:
Marianna [84]4 years ago
3 0
I would go with the first one
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A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
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With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

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m_{AB}=\frac{8-5}{1--5}

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<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

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<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

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If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




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