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cricket20 [7]
3 years ago
12

Please help pls and ty​

Mathematics
1 answer:
natali 33 [55]3 years ago
7 0
No because the exact opposite of -3 would be 3.
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Question 5
Stells [14]

Answer:

7**6

Step-by-step explanation:

The expression 7^6 ; can be interpreted as 7 raised to the power of 6 ; which is (7 * 7 * 7 * 7 * 7 * 7). To execute this expression using a computer or basic mathematical operation on a computer we use the power symbol which the computer understand this the double multiplication symbol (**)

Hence, 7^6 = (7**6)

7 0
3 years ago
A packet of vegetable seeds has a germination rate of
Doss [256]

N = number of seeds planted

P = probability of germination

K = number that germinated

Using probability calculation:
p(x = k) = (n k) x 0.90^K x 0.10^n-k


p(10) = (12 10) x 0.90^10 x 0.10^2

P(10) = 0.2310

8 0
2 years ago
How do you calculate the mean, medium, and range of the data in a dot plot?
adelina 88 [10]
Add all numbers and divide the total by how many numbers there are
8 0
3 years ago
What is ten times as much as 0.09
Sophie [7]
The answer you are searching for is .9
3 0
3 years ago
Read 2 more answers
Can someone please explain how to solve this step by step with answer? Thank you.
lidiya [134]

a)

well, she put 4000, and she earned in interest 960, so her accumulated amount is just their sum, 4960.

b)

now, it doesn't say, so we're assuming is <u>simple interest</u>, as opposed to compound interest.


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&960\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to r\%\to \frac{r}{100}\dotfill\\ t=years\dotfill &3 \end{cases} \\\\\\ 960=(4000)(r)(3)\implies \cfrac{960}{(4000)(3)}=r\implies 0.08=r \\\\\\ \stackrel{\textit{converting to percentage}}{r=0.08\cdot 100}\implies r=\stackrel{\%}{8}


c)

let's make the rate 1% greater then, and check


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to \stackrel{8+1}{9\%}\to \frac{9}{100}\dotfill&0.09\\ t=years\dotfill &3 \end{cases} \\\\\\ I=(4000)(0.09)(3)\implies I=1080 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{at 9\%}}{1080}-\stackrel{\textit{at 8\%}}{960}\implies \stackrel{\textit{that much more}}{120}

4 0
3 years ago
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