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Rudik [331]
2 years ago
12

Broo please help me omg

Mathematics
1 answer:
tester [92]2 years ago
3 0

Answer:

9. -2

10. 0

Step-by-step explanation:

It is not undefined because the slope of horizontal lines are 0

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In the formula p=kt find t when k=36 and p=144
stepan [7]

Answer:

t=4

Step-by-step explanation:

solve for t by deciding both sides by k.

then do 144/36 to get t.

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2 years ago
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A(n) ___ expression is an expression that contains a radical symbol.
Alla [95]

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radical

Step-by-step explanation:

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Find the distance between the pair of points (-3, 1) and (2, 1)
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The answer to your question is 5
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3(y - 3) = -15<br> I really need help
Tomtit [17]

Answer:

y=-2

Step-by-step explanation:

can i get brainliest please???

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The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 mi
dem82 [27]

Answer:

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require more than 15 minutes to grade

This is 1 subtracted by the pvalue of Z when X = 15. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 16.3}{4.2}

Z = -0.31

Z = -0.31 has a pvalue of 0.3783.

1 - 0.3783 = 0.6217

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

8 0
3 years ago
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