Answer:
Step-by-step explanation:
This quadratic models the parabolic motion equation

where h is the height of the object after the motion occurs, a is the pull of gravity, v(i) is the initial vertical velocity of the object, and h(i) is the height from which the object was initially launched. If we are looking for when the ball hits the ground, h = 0, because the height of an object on the ground has no height at all (or 0 height). To find the time the object was in the air, factor the quadratic and solve for the values of t.
Two factors of 4 that add up to be 3 and multiply to be 4 are -1 and 4. So t=-1 and t = 4. Since we know that time can never be negative, then t = 4 seconds.
We have been given an equation of circle
. We are asked to find the center and radius of the circle.
First of all, we will write equation of circle is standard form
, where center of circle is at point (h,k) and radius is r.
Let us complete the square for both x and y.


Adding half the square of coefficient of x and y term, we will get:





Therefore, the center of the circle is
and radius is 4 units.
45 = (x) + (x + 1) + (x + 2)
45 = 3x + 3
- 3
42 = 3x
/3
14 = x
45 = 14 + (14 + 1) + (14 + 2)
45 = 14 + 15 + 16
The ages of the 3 friends are 14, 15, and 16.
Length: w+4
Width:w
Perimeter:44
Area: L times w
P=44
44=2(w)+2(w+4)
44=2w+2w+8
44=4w+8
36=4w
w=9
L=w+4
L=9+4
L=13
Area should equal 117 cm squared