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3 years ago

A=1/2bh, solve for b

1 answer:

3 0

Answer: b=2A/h.

First, multiple both sides of the equation (A=1/2bh) by 2. You should be left with bh=2A.

Divide both sides of the equation by h. You should be left with b=2A/h.

Hope that helped!

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3 years ago

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Answer:

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Step-by-step explanation:

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vovangra [49]

Answer:

${6x}^{3} + {9x}^{2} - 18x + 3$

Step-by-step explanation:

1. Expand by distributing sum groups. $3x( {2x}^{2} + 5x - 1) - 3( {2x}^{2} + 5x - 1)$

2. Expand by distributing terms.

${6x}^{3} + {15x}^{2} - 3x - 3( {2x}^{2} + 5x - 1)$

3.Expand by distributing terms.

${6x}^{3} + {15x}^{2} - 3x - ( {6x}^{2} + 15x - 3)$

4. Remove parentheses.

${6x}^{3} + {15x}^{2} - 3x - {6x}^{2} - 15x + 3$

5. Collect like terms.

${6x}^{3} + {15x}^{2} - {6x}^{2} ) + ( - 3x - 15x) + 3$

6. Simplify.

${6x}^{3} + {9x}^{2} - 18x + 3$

Thus. the answer is,

${6x}^{3} + {9x}^{2} - 18x + 3$

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Step-by-step explanation:

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