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siniylev [52]
3 years ago
12

Answers please. First to answer all of them correctly gets brainliest.

Mathematics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

1: Graph 4

2: Graph 2 (the first one in the third picture)

3: I got $422, so $420, is probably the correct answer.

Step-by-step explanation:

If I helped, a brainliest would be greatly appreciated!

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Two forty- four plus what equals two sixty-nine
Pavlova-9 [17]

Assuming you mean 244+?=269, the answer is 25. Hope this was right

7 0
2 years ago
Read 2 more answers
Estimat the product of 32*36
7nadin3 [17]
32(40-4)
32*40 - 32*4
1,280 - 128=
1,152
therefor
32*36= 1,152
4 0
3 years ago
If f is a continuous function such that the integral from 1 to 4 of f of x, dx equals 10, evaluate the integral from 2 to 8 of 2
IgorLugansk [536]

Answer: 10

Step-by-step explanation:

Since integral from 1 to 4 of f(x) =10

To evaluate integral from 2 to 8 of 2 times f(2x), using substitution method

Let U = 2x, dU = 2dx, dx = dU/2

Evaluate the limit, upper limit gives dU = 2*4 = 8, lower limit gives dU = 2*1 = 2.

Since this limit are the same as the limit for the question,

Therefore, F(4) - F(1) = F(8) - F(2) = 10

Substituting dx=dU/2

Gives,

Integral from 2 to 8 of 2 times f(2x)= (1/2)(2)(F(8)-F(2)) = 10

6 0
3 years ago
You want to test the effect of light on the distribution of Artemia in your 35cm long testing chamber. If you measure the light
Dvinal [7]

Answer:

64.3 lumens

Step-by-step explanation:

Data provided in the question:

Length of the testing chamber = 35 cm

Light at one end = 10 lumens

Light at other end = 200 lumens

now,

since the variation is linear,

therefore, the gradient of the variation

= \frac{200-10}{35}

= 5.43

also,

the darkest end is the end with 10 lumens

therefore,

The lumens at 10 cm from the darkest end

= 10 + 5.43(10)

= 10 + 54.3

= 64.3 lumens

6 0
3 years ago
Can you please explain how to write the ratios for sin x and cos x? When angles are x, y, and z. The hypotenuse being 12 and is
Kamila [148]
Your triangle has acute angles X and Y, and right angle Z.

For an acute angle A in a right triangle:

The sine is the ratio of the opposite leg to the hypotenuse.
sin A = opp/hyp

The cosine is the ratio of the adjacent leg to the hypotenuse.
cos A = adj/opp

The hypotenuse of a right triangle is the side opposite the right angle. It is the longest side of a right triangle. There is only one hypotenuse in a triangle, so there is no confusion with the hypotenuse.

The two sides that form the right angle are called the legs. Each leg is opposite an acute angle. The legs may or may not be congruent to each other, but each leg is always shorter than the hypotenuse. Since there are two legs, we need to be able to distinguish them. If you take an acute angle as your angle of interest, the leg that is part of the angle is called the adjacent leg. The other leg is the opposite leg. Adjacent leg and opposite leg are relative terms. They depend on the acute angle you are considering.

For your triangle, if you look at angle X, then the adjacent leg is side XZ. The opposite leg for angle X is side YZ.

Using the ratios mentioned above for sine and cosine, you get:

sin X = opp/hyp = sqrt(119)/12

cos X = adj/hyp = 5/12
7 0
3 years ago
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