3(1)^2-3= 0
Plug in the numbers because x=1 plug In 3(1)^2 and it equals 3 then subtract y which is 3-3= 0
28.7083333333...
But you could also round it up to 29.
Let 
be the dimensions of the rectangle. We know the equations for both area and perimeter:
So, we have the following system:
From the second equation, we can deduce
Plug this in the first equation to get
Refactor as
And solve with the usual quadratic formula to get
Both solutions are feasible, because they're both positive.
If we chose the positive solution, we have
If we choose the negative solution, we have
So, we're just swapping the role of 
and 
. The two dimensions of the rectangle are 
and 
Answer:
x-6/x²-x-30
Step-by-step explanation:
(x-6)(x+5)
x²-x-30
when you factor out x-6 you have a removable discontinuity and you have x+5 as your denominator and that would be the vertical asymptote since you can have a 0 as your denominator the V.A. would be x = -5.
