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Nat2105 [25]
3 years ago
5

Witch number is 1.2 and 1.4 on the number line

Mathematics
1 answer:
sammy [17]3 years ago
7 0

Answer:

What numbers are 1.2 and 1.4 on the number line? Huh?

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Given the Homogeneous equation x^2ydy+xy^2dx=0, use y=ux, u=y/x and dy=udx+xdu to solve the differential equation. Solve for y.
scZoUnD [109]

Answer:

y=\frac{C}{x}.

Step-by-step explanation:

Given homogeneous equation

x^2ydy+xy^2dx=0

\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{xy^2}{x^2y}

Substitute y=ux , u=\frac{y}{x}

\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{y}{x}

Now,

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=\frac{\mathrm{d}y}{\mathrm{d}x}

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=-u

\frac{\mathrm{d}u}{\mathrm{d}x}=-2u

\frac{du}{u}=-\frac{dx}{x}

Integrating both side we get

lnu=-2lnx+lnC

Where lnC= integration constant

lnu+ln{x}^2=lnC

lnux^2=lnC

Cancel ln on both side

ux^2=C

Substitute u=\frac{y}{x}

Then we get

xy=C

y=\frac{C}{x}.

Answer:y=\frac{C}{x}.

8 0
3 years ago
Solve 4(3r + 4) - 6(r + 1) =22
Fofino [41]

Answer:

r = 2

Step-by-step explanation:

4(3r + 4) - 6(r + 1) =22

12r + 16 - 6r - 6 = 22

6r = 12

r = 2

7 0
3 years ago
11. Mir. Ed earns $14.50 per hour. His regular hours are 40 hours per week, and he
faust18 [17]

Answer:

$688,75

Step-by-step explanation:

Mr Ed has for the week 40 hours in regular time because thats the agreement for him and the company, it means any other working hour is over time.

If Mr Ed has 45 hours for this week, 40 hours are regular time and 5 hours are over time for wich he receives 1,5 times his pay per hour

=(40x14,50)+(5x1,5x14,50)

=$688,75

3 0
3 years ago
A landscaper makes a $2,000 profit in a week when he services 25 lawns. he makes a $600 profit in a week when he services 11 law
aleksandrvk [35]

Answer:

$3,100

Hope this helps!!

4 0
2 years ago
Find the perimeter. (attachment included)
Tresset [83]

Answer:

5 + 2\sqrt{11}

Step-by-step explanation:

5 + \sqrt{11} - \sqrt{5} + \sqrt{11} + \sqrt{5}

5 + 2\sqrt{11} -  \sqrt{5} + \sqrt{5}

5 + 2\sqrt{11}

6 0
3 years ago
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