Helpppp meee plsssss

The question is in the image.

zepelin [54]

Answer:

Both are linear functions.

Step-by-step explanation:

There are no same x values in the table and the graph passes the vertical line test.

6 0

2 years ago

(Please need help )Cedrick traded his Halloween candy with his friends. He likes Snickers as his favorite

Vesna [10]

Answer:

87.5%

Step-by-step explanation:

28/32=0.875

0.875*100= 87.5

87.5% of 32 = 28

3 0

2 years ago

The short sides 6cm The long sides twice the short size what is the perimeter

Doss [256]

The perimeter is 36.

5 0

3 years ago

Which statement describes the inverse of m(x) = x2 – 17x?

stealth61 [152]

Answer:

The correct option is;

$The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}$

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

$x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

$x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}$

Which can be simplified as follows;

$x = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2} \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}$

And further simplified as follows;

$x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}$

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

$m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}$

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

$The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}$ to increase m⁻¹(x) above the minimum.

8 0

2 years ago

3 a western beach is reducing width by 10 feet every 5 years for the first 10 years the patter then became less constant dunes b

Anna71 [15]

A. Western Beach is reducing was width by 10 feet every 5 years for the first 10 years, then the pattern became less constant. Dunes Beach experienced a stable and fast increase in width, 25 feet every 5 years of 5 feet per year.

B. Somewhere between years 11 and 12 they had the same width.

C. You can place the values on a graph and connect the points, and look at the intersections to determine points in time where they were of the same width.

First, lets look at the data. Western Beach (or WB for short) decreases its width by 10 feet every 5 years from year 0 to year 10. Between year 11 and year 15 the pattern shifts and becomes less changing since there is barely any change between years 12 and 15. Dunes Beach (or DB) increases steadily by 25 feet every 5 years or 5 feet per year.

Assuming the changes in width happen over time and gradually, at some point between year 10 and 11, both beaches would have likely had the same width, somewhere between 70 and 75.

To determine the exact point in time where they meet we would need to draw a graph, with the width in feet on the X axis and the year on the Y axis. Then we place all the pairs in the graph by their coordinates, and connect the points that correspond to each beach. We then see where the lines intersect and use mathematics to determine the values of X and Y, giving us the time and width when the two beaches were equal.

please mark me brainliest it helps to become an genius

4 0

2 years ago