Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:
If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:
w=7.5x1.48 tons
w=11.1 tons
The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?
1 container-------3.7 tons of gravel
x-------11.1 tons of gravel
x=(11.1x1)/3.7
x=11.1/3.7
x=3 containers
H<span>ow many containers of this size are needed to hold all the gravel from one truck?
</span>
The answer is: 3 containers.
The value of TV is 11.
<h3>What is equation?</h3>
An equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Given:
TU= 8, UV = 3x and TV = x+10
TV= TU + UV
x +10= 8+ 3x
-2x = -2
x= 1
Hence, TV = 1+10= 11.
Learn more about equation here:
brainly.com/question/10413253
#SPJ1
Answer:
1/12
Step-by-step explanation:
3/4=9/12
12/12-9/12=3/12
(3/12)/3=1/12
